Can you determine the fee for 30 ride tickets?

1 answer:

7 0

I don't know how much the fee is so I will just write an equation to help you figure it out.

30x
x=the fee for one ride ticket.

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Suppose the test scores on an exam show a normal distribution with a mean of 82 and a standard deviation of

Zanzabum

Answer:

a) Between 74 and 90

b) 81.86% of the scores are between 78 and 90

Step-by-step explanation:

a) According to the Empirical Rule, in a normal distribution, 95% of the data are within 2 standard deviations of the mean. Therefore, the range that 95% of the scores fall in is between 82-4(2)=74 and 82+4(2)=90.

b) The percent of scores that are between 78 and 90 is: normalcdf(lower,upper,μ,σ) = normalcdf(78,90,82,4) = 0.8185946784 ≈ 0.8186, or about 81.86% of the scores.

5 0

3 years ago

Answer the questions by drawing on the coordinate plane below.

solniwko [45]

Coordinates of the given triangle ΔPQR P(1,-1), Q(3,-2), R(3,-4).

a) Let us discuss the rule for rotation of 90° clockwise about the origin.

If given coordinate is (h,k) is rotated 90° clockwise about the origin the position of rotated coordinate will be (k, -h).

x and y coordinates would switch their values and after switching x any values, the y value of the coordinates would reverse in sign.

So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become

P(1,-1) --> P'(-1,-1)

Q(3,-2) --> Q'( -2,-3)

R(3,-4) --> R'(-4,-3)

b) If given coordinate is (h,k), the coordinates after reflection across the x-axis would besome (h,-k). (Just change in the sign of y-coordinate).

So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become

P(1,-1) --> P"(1,1)

Q(3,-2) --> Q"( 3,2)

R(3,-4) --> R"(3,4)