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Misha Larkins [42]
2 years ago
11

What is 1/9 of 9? a) 1/9 b) 0 c) 1 d) 2 e) 3

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
6 0

\implies {\blue {\boxed {\boxed {\purple {\sf {c) \:1}}}}}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

=  \frac{1}{9}  \times 9\\

=  \frac{9}{9} \\

=  \frac{1}{1} \\

= 1\\

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}

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The volume of the square pyramid is 147 centimeters.
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Which is Greater?<br><br> 0.034 or 0.04
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If an electric kettle uses
cupoosta [38]

Answer:

The energy used in 3.5 hours = 5.25 kilowatts            

Step-by-step explanation:

Energy used by electric kettle:  

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Time taken by electric kettle:

  • 1.5 hours

Electric kettle's rate in kilowatts per hour can be calculated by dividing the spent energy i.e. 2.25 kilowatts by the time taken i.e. 1.5 hours.

Therefore,

Electric kettle's rate = 2.25 kilowatts / 1.5 hour

                                  = 1.5 kilowatts per hour

Thus, the energy used in 3.5 hours = 1.5 × 3.5

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Therefore, the energy used in 3.5 hours = 5.25 kilowatts                        

3 0
3 years ago
Monomials. Please help. I have a test<br> (m^8)^5
cricket20 [7]

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8 0
2 years ago
Write the equation of circle b with center B(-2,3) that passes through (1,2)
professor190 [17]

Answer:

(x+2)^2 + (y-3)^2 = 10

Step-by-step explanation:

The standard equation for circle is

(x-a)^2 + (y-b)^2 = r^2

where point (a,b) is coordinate of center of circle and r is the radius.

______________________________________________________

Given

center of circle =((-2,3)

let r be the radius of circle

Plugging in this value of center in standard equation for circle given above we have

(x-a)^2 + (y-b)^2 = r^2    \ substitute (a,b) \ with (-2,3) \\=>(x-(-2))^2 + (y-3)^2 = r^2  \\=>(x+2)^2 + (y-3)^2 = r^2    (1)

Given that point (1,2 ) passes through circle. Hence this point will satisfy the above equation of circle.

Plugging in the point (1,2 )  in equation 1 we have

\\=>(x+2)^2 + (y-3)^2 = r^2    \\=> (1+2)^2 + (2-3)^2 = r^2\\=> 3^2 + (-1)^2 = r^2\\=> 9 + 1 = r^2\\=> 10 = r^2\\=>  r^2  = 10\\

now we have value of r^2 = 10, substituting this in equation 1 we have

Thus complete equation of circle is =>(x+2)^2 + (y-3)^2 = r^2\\=>(x+2)^2 + (y-3)^2 = 10

7 0
3 years ago
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