Given the replacement set {0,1,2,3,4} .solve 6x-3=3

Factorise <br> a) 3x^2-7x+2<br> b)2x^2-x-3<br> c)3x^2-16x-12

Luba_88 [7]

Answer: Answers are in the steps read carefully!

Step-by-step explanation:

A) 3x^2 - 7x + 2 To factor this polynomial, you have to find two numbers that their product is 6 and their sum is -7. The numbers -1 and -6 works out because -6 times -1 is 6 and -6 plus -1 is -7.

Now rewrite the polynomial as

3x^2 - 1x - 6x + 2 Now group it

(3x^2 - 1x) (-6x+2) Factor it by groups

x (3x -1) -2(3x -1) Now factor out 3x-1

(3x -1) (x-2) Done!

B) 2x^2 - x -3 Now the same way.You will have two numbers that their product is -6 and their sum is -1. You may be wondering how I get -6 .I get -6 by multiply the leading coefficient 2 by the constant -3. The numbers -3 and 2 works out. Because -3 times 2 is -6 and -3 plus 2 is -1.

Rewrite the polynomial as

2x^2 +2x - 3x -3 GRoup them and factor them

(2x^2 + 2x) (-3x-3)

2x(x+1) -3(x+1) Factor out x+1

(x+1) (2x -3) Done!

C) 3x^2 - 16x - 12 Find two numbers that their product is -36 and their sum is -12. The numbers -18 and 2 works out because -18 times 2 is -36 and -18 plus 2 is -16.

Rewrite the polynomial

3x^2 +2x -18x - 12 GRoup them

(3x^2 + 2x) (-18x - 12) Factor them

x (3x +2) -6(3x +2) Factor out 3x+2

(3x+2) (x -6) Done !

6 0

4 years ago

Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

a=

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0

3 years ago

Evaluate [3+(8-2)]x5

photoshop1234 [79]

Answer:

45

Step-by-step explanation:

Subtract the numbers

(3+(8-2)). x5

[3+6)]. x5

Add the numbers

[3+6]. x5

[9]. x5

8 0

3 years ago

You pick a card at random. You put the first card back, and you pick a second card at

Fudgin [204]

Answer:

Step-by-step explanation:

maybe 8 or 1/9

8 0

3 years ago

Mr. Hong brought his 7 year-old daughter, Jin and his 10 year-old son, Cai, to Redwood Amusement Park. An Admission ticket coste

kompoz [17]

$20.25 because 8.50 and 8.50 equal 17 and then subtract 2.00 makes 15, and then add 5.25 and you end up with 20.25

4 0

3 years ago