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ivolga24 [154]
3 years ago
11

you have diving lessons every fifth day and swimming lessons every third day today you have both lessons in how many days will y

ou have both lessons on the same day again
Mathematics
1 answer:
olganol [36]3 years ago
8 0
Mondays, Tuesdays, Wednesdays.
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Solve y/2 + 22 =38 for y
KATRIN_1 [288]

Answer:

y = 32

Step-by-step explanation:

\frac{y}{2}+22=38\\\frac{y}{2}=16\\y=32

4 0
2 years ago
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Martin burns 360 calories running for 30 minutes. Paul burns 165 calories for every 15 minute he runs. If Kara runs for 20 minut
Yanka [14]

Answer:  She would have to burn between 220 and 240 calories per minute to have a calorie burn rate between those of Martin and Paul.

Step-by-step explanation:

Martin:

360 calories / 30 min = 12 calories/min

Paul:

165 calories / 15 min = 11 calories/min

Kara:

Needs to burn between 11 and 12 calories/min, so we'll calculate the range:

11 calories/min x 20 min = 220 calories (minimum # calories she can burn)

12 calories/min x 20 min = 240 calories (maximum # calories she can burn)

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3 years ago
What is the answer to 9x-7i>3(3x-7u)
Jlenok [28]

Answer:

undefined

Step-by-step explanation:

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3 years ago
The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged
Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

  • X is the left atrial diameter value we are looking for its z-score
  • M is the mean left atrial diameter of healthy children (26.7 mm)
  • s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

5 0
3 years ago
Hi can anyone plz help me with this and can you explain how you got it ​
zloy xaker [14]

Answer:

What to prove, solve for?

6 0
3 years ago
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