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3 years ago

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the science club sold homemade cupcakes to raise money for a hiking trip they sold the cupcakes for 75 cents each they spent $38

.54 baking ingredients and make a profit of $105.50 write and solve the equation to determine the number of cupcakes the science club sold

1 answer:

AleksandrR [38]3 years ago

3 0

Well 105.50 \ 75 = 1.40 cents so 75 x 1.40 = 105 cupcakes sold by the science club

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Last year the backgammon club had 30 members this year the club has 24 members find the percent of decrease of members

olchik [2.2K]

Answer:

Percent Decrease = 20% Decrease

Step-by-step explanation:

To find percentage decrease, we will use a simple formula shown below:

Percentage Decrease/Increase = $\frac{New-Old}{Old}*100$

Where

New is the latest number of members (which is 24)

Old is the initial number of members (which is 30)

<em>Note: the multiplication by a factor of "100" brings the answer to a percentage</em>.

Now, lets substitute the numbers and figure out the percentage decrease:

$\frac{New-Old}{Old}*100\\\frac{24-30}{30}*100\\\frac{-6}{30}*100\\-0.2*100\\-20$

So, it comes to -20, which is a decrease of 20%

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3 years ago

Halp me pls..<br> !!!!<br><br><br> :D I will be happy

pochemuha

The probability of multiple events happening is found by multiplying the probabilities of each event together.

$P_{d+even\ number}=P_{d}*P_{even}\\\\P_{d}=\frac{number\ of\ events}{total\ number\ of\ events}=\frac{(d)}{a,\ b,\ c,\ d,\ e)}=\frac{1}{5}\\\\P_{even}=\frac{number\ of\ events}{total\ number\ of\ events}=\frac{(2,\ 4,\ 6)}{(1,\ 2,\ 3,\ 4,\ 5,\ 6)}=\frac{3}{6}=\frac{1}{2}\\\\\frac{1}{5}*\frac{1}{2}=\boxed{\frac{1}{10}}$

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3 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

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with $0\le t\le1$ .

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$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

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d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

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$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

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3 years ago

0.729 rounded by the nearest tenth

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2 years ago

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