Given:
Consider the equation is:
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Some steps of the solution are given.
To find:
The next step of the solution.
Solution:
Step 1: The given equation is:

Step 2: Simplifying right hand side.

Step 3: Simplifying left hand side.

These steps are already given. So, the next step is:
Step 4: Subtracting 3 from both sides.

Therefore, the correct option is (b).
Answer:
Q1:
A: 0.1666
B: 0.4
C: 0.18181818
Step-by-step explanation:
Answer: 11113200
Step-by-step explanation:
We know that , the number of combination of choosing r things from n things is given by :-

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-
Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-
Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-


∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200