Answer:
x = 500 yd
y = 250 yd
A(max) = 125000 yd²
Step-by-step explanation:
Let´s call x the side parallel to the stream ( only one side to be fenced )
y the other side of the rectangular area
Then the perimeter of the rectangle is p = 2*x + 2* y ( but only 1 x will be fenced)
p = x + 2*y
1000 = x + 2 * y ⇒ y = (1000 - x )/ 2
And A(r) = x * y
Are as fuction of x
A(x) = x * ( 1000 - x ) / 2
A(x) = 1000*x / 2 - x² / 2
A´(x) = 500 - 2*x/2
A´(x) = 0 500 - x = 0
x = 500 yd
To find out if this value will bring function A to a maximum value we get the second derivative
C´´(x) = -1 C´´(x) < 0 then efectevly we got a maximum at x = 500
The side y = ( 1000 - x ) / 2
y = 500/ 2
y = 250 yd
A(max) = 250 * 500
A(max) = 125000 yd²
Answer:
300
Step-by-step explanation:
because when multiply then divide all of them then find a percent 300 is your answer
Answer:
The length of the rectangle is 37 yards, and the width of the rectangle is 17 yards.
Step-by-step explanation:
Given that the length of a rectangle is 3 yards more than twice the width, and the area of the rectangle is 54 yards, the following calculation must be performed to find the dimensions of the rectangle, knowing that the area of a rectangle arises from multiplying its base by its height:
2X + 3 + X = 54
3X + 3 = 54
3X = 54 - 3
X = 51/3
X = 17
(17 x 2) + 3 = 37
Therefore, the length of the rectangle is 37 yards, and the width of the rectangle is 17 yards.
I'm pretty sure its line c.
Step-by-step explanation:
Answer:
I dont understand that sorry
