The original price for one lunch special is $19.
<em><u>Explanation</u></em>
The original price for one lunch special is 'p' dollar.
He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay
dollar each day</u>.
So, the total amount needed to pay for 5 days
dollar
Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....
![5(p-4)= 75\\ \\ 5p-20=75\\ \\ 5p= 75+20\\ \\ 5p= 95\\ \\ p=\frac{95}{5}=19](https://tex.z-dn.net/?f=5%28p-4%29%3D%2075%5C%5C%20%5C%5C%205p-20%3D75%5C%5C%20%5C%5C%205p%3D%2075%2B20%5C%5C%20%5C%5C%205p%3D%2095%5C%5C%20%5C%5C%20p%3D%5Cfrac%7B95%7D%7B5%7D%3D19)
So, the original price for one lunch special is $19.
Answer:
17.1
Step-by-step explanation:
Answer:
65.3
Step-by-step explanation:
89.10 - [(1.20 × 31)+ (4.90 + 7)]
89.10 - [37.2 + 11.9]
89.10 - 23.8
= 65.3