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3 years ago

I am a quadrilateral

Mathematics

2 answers:

Gwar [14]3 years ago

7 0

Answer:

Square

Step-by-step explanation:

Squares are quadrilaterals

Squares have two sets of parallel sides

Squares have four right angles

Squares sides are all congruent.

KatRina [158]3 years ago

6 0

The shape is a square

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a reduced fat cookie contains 11g of fat per serving. in order for food to be termed 'reduced fat', it must have at least 20% le

Svetllana [295]

Personally, I did this in a kinda weird way but I think that it should be correct

-How I figured the answer out-

I took 11g and wrote 80% next to it, because after all it has 80% less fat than the regular cookie.

Then, I scaled it down to 10% by dividing by 8, which got me

1.375g = 10%

And finally, I multiplied by 10 to now have 100% (meaning, a regular serving size cookie) and be left with the result: 13.75g

-The answer-

13.75g (don't forget to write the units)

Have a great day :)

6 0

3 years ago

In this equation, identify the following:

sladkih [1.3K]

Answer:

-3 constant , x variable +7 constant

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3 years ago

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Your class is selling boxes of flower seeds as a fundraiser. The total profit p depends on the amount x that your class charges

Slav-nsk [51]

Answer:

$ 22.6

Step-by-step explanation:

Given that

Price charged for each box of seeds = x

Profit gained from from selling boxes of seeds = p

The equation of profit is modeled as

P(x) = 0.5x² + 36x - 179

As per given information if the fundraisers make a profit of $379 then find the minimum price charged for each box of seed.

Now our above equation becomes

379 = -0.5x² + 36x - 179

Simplifying

379+179 = -0.5x² + 36x

558 = -0.5x² + 36x

0.5x² - 36x + 558 =0

multipying both sides of equation by 2

2(0.5x² - 36x + 558) = 2x0

x² - 72x +1116 = 0

Using quadratic formula we get the following factors

x= 49.4 or x= 22.60

As we can the smalles value is 22.6

So, they can charge 22.6 dollar for each bag of seeds in order to get profit of 379 dollars.

8 0

3 years ago

Read 2 more answers

Marty and Ethan both wrote a function, but in different ways.

lisabon 2012 [21]

Answer:

Marty's function has larger slope as compared to Ethan's slope.

Step-by-step explanation:

Marty function:

y plus 3 equals StartFraction 1 Over 3 EndFraction left-parenthesis x plus 9 right-parenthesis.

Writing in mathematical form: $y+3=\frac{1}{3}(x+9)$

Marty has written expression in point-slope form: $y-y_1=m(x-x_1)$ where m is slope

So, comparing Marty's equation with general point-slope form equation we get slope $m=\frac{1}{3}\:or\: 0.3$

Now, Ethan has a table

x y

-4 9.2

-2 9.6

0 10

2 10.4

We can find slope using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

Using any two points, we can find slope of Ethan's equation

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{9.6-9.2}{-2-(-4)} \\Slope=\frac{0.4}{-2+4} \\Slope=\frac{0.4}{2} \\Slope=0.2$

So, we get Marty's slope = 0.3

Ethan's slope = 0.2

So, Marty's function has larger slope as 0.3 is greater than 0.2

6 0

3 years ago

Read 2 more answers

Fill in the blank. In a drive thru performance study, the average service time for McDonald's is 203.21 seconds with a standard

Alenkasestr [34]

Answer:

5) 203.35

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .