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Serjik [45]
3 years ago
13

Solve the proportion 15t/5=2t +3 /6.

Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0
<span>15t/5=2t +3 /6
3t = 2t + 1/2
3t-2t = 1/2
t = 1/2

So, your final answer is 1/2

Hope this helps!
</span>
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Three students are arguing over who can run the fastest. Student A says that she can run 2/3 mile in six minutes. Student B says
harkovskaia [24]
1/10 



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8 0
3 years ago
The odds of flipping a fair coin either heads or tails is 50%. The odds of rolling a six on a fair six sided die is 16.6% or 1 i
creativ13 [48]

Answer:

P( sum is prime )= 73/216

Step-by-step explanation:

The minimum value of the sum will be 3 and maximum value will be 18. So the prime numbers in this range are 3 , 5, 7, 11, 13, 17.

P(sum=3)=1/216, P(sum=5)=6/216, P(sum=7)=15/216, P(sum=11)=27/216, P(sum=13)=21/216, P(sum=17)=3/216.

The final probability will be sum of the above given probabilities.

Hence P( sum is prime )= 73/216

8 0
3 years ago
A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
RoseWind [281]

Answer:

There is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.

Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the average height of male students at a large college is, (63.5 inches, 74.4 inches).

The 95% confidence interval for the average height of male students (63.5, 74.4) implies that, there is a 0.95 probability that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Or, there is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

4 0
3 years ago
Write (-2 − 2i) + (10 − 4i) as a complex number in standard form.
romanna [79]

Answer:

8-6i

Step-by-step explanation:

complex number in standard form will be in the form of a+bi

(-2 − 2i) + (10 − 4i) , open parenthesis

-2- 2i +10 -4i, group like terms

-2+10 -2i -4i, combine like terms

8 - 6i

7 0
2 years ago
If
Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by \sqrt{x}

b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x}  }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\

Now, find a +b

a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}

Combine like terms

= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}

Now find (a + b)²

(a +b)² = (\frac{2\sqrt{x} }{x})^{2}

          = \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}

Hint: \sqrt{x} *\sqrt{x}  =\sqrt{x*x}=x

5 0
2 years ago
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