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tangare [24]
3 years ago
9

The masses of four planets in a solar system outside the Milky Way are given below.

Mathematics
1 answer:
zhenek [66]3 years ago
7 0
Your answer is Planet B, Planet D, Planet A, Planet C. 
Look at the exponents.
23 comes before 24 and 27. So 3.30 x 10 ^ 23 comes first. Next, 24, and there are 2, so  go by the decimals, 4.87 comes before 5.97. So 4.87 x 10^24 comes before 5.97 x 10^24. Then, that leaves 1.89 x 10^27.
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3 years ago
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zheka24 [161]

Answer:

25 is the area because5 times 5 equals 25

Step-by-step explanation:

hope this helps

4 0
3 years ago
Read 2 more answers
7. The jib sail of a yacht is
Rom4ik [11]

Answer:

Pytagora's Theorem

Step-by-step explanation

a = 4 m

b = 15 m

c = ?

a^2 + b^2 = c^2

√ a^2 + b^2 = c

a^2 = 16 m

b^2 = 225 m

√  16 + 225 = c

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4 0
3 years ago
HELP
Yakvenalex [24]

Answer:

5. 50.3 m²

6. 113.1 cm²

7. 102.1 yards²

8.  50.3 yards²

9.  452.2 ft²

10.379.8 ft²

Step-by-step explanation:

Area of  a circle = nr²

The circumference of a circle = 2nr

n = pi = 22/7

r = radius

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

radius = diameter / 2

5. (22/7) x 4² = 50.3 m²

6.  (22/7) x 6² =113.1 cm²

7. radius = 11.4/2 = 5.7 yards

(22/7) x 5.7² =102.1 yards²

8. radius = 8/2 = 4 yards

(22/7) x 4² = 50.3 yards²

9. 2nr = 75.4 yards

2 x (22/7) x r = 75.4

to find r, divide both sides of the equation by 2 and 7/22

r = 12 ft

Area =  (22/7) x 12² = 452.2 ft²

10. 2nr = 69.1 yards

2 x (22/7) x r = 69.1

to find r, divide both sides of the equation by 2 and 7/22

r = 10.99 ft²

Area = (22/7) x 10.99² = 379.8 ft²

the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

8 0
3 years ago
A shelf in the Metro Department Store contains 90 colored ink cartridges for a popular ink-jet printer. Five of the cartridges a
belka [17]
A ) 
P ( x = 3 ) = 5/90 * 4/89 * 3/88  = 1 / 11,748 = 0.000085
b ) 
Probability of selecting zero defective cartridges:
P ( x = 0 ) = 85/90 * 84/89 * 83/88 = 592,620 / 704,880 = 0.840739
P ( at least 1 defective) = 1  -  0.840739 = 0.159261 
4 0
3 years ago
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