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LUCKY_DIMON [66]
3 years ago
6

Lmk ASAP please

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
4 0
I need to sell 2 homes
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What’s the total value of the 6 in 26,312
Orlov [11]
The total value is 6,000
5 0
3 years ago
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6. The diagram on the right shows the cross-section of a cylindrical pipe with water lying in the bottom. a) If the maximum dept
riadik2000 [5.3K]

Answer:

404 cm³ Anyway... Look down here for my explanation.

Step-by-step explanation:

Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.

We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)

44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°

The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.

Shaded area 88.8/360*area of circle - ½*7*788.8°

= 88.8/360*π*7² - 24.5*sin 88.8°

13.5 cm²

(using area of ∆ = ½.a.b.sin C for the triangle)

Volume of water = cross-sectional area * length

13.5 * 30 cm³

404 cm³

6 0
1 year ago
I need the answer ASAP please
lara [203]

a \leq 7

because 4a + 7 - 7 \leq 35 - 7

equals 4a \leq 28

and 4a/4 \leq 28/4

equals a \leq 7

5 0
3 years ago
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Mr. rodriquez was on the telephone for 182 minutes. She called 7 friends to invite them to a luncheon. If she spoke to each frie
vitfil [10]
He spoke to each friends for 26 minutes

How I found out : how I found out is that all you have to do it get the total amount which in this question it is going to be 182. And you would need to dive 182 by 7 to find the unit rate (182/7) which is going to equal 26.which means he called each friend for 26 minutes
5 0
3 years ago
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Express this in standard form 5.4×10^1​
Naily [24]
Well it would just be 54 since you just need to move the decimal over by 1.

So 5.4x10= 54
7 0
3 years ago
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