1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aniked [119]
3 years ago
10

Ethan rode 25.65 kilometers on Saturday and 14.23 kilometers on Sunday. About how far did Ethan ride during the two days?

Mathematics
2 answers:
Anna35 [415]3 years ago
7 0
39.9
Hope this helps!!!
vazorg [7]3 years ago
3 0
So for this problem we are looking for a sum (total). So first we are going to round 25.65 to 25.7 and round 14.23 to 14.2

Now we are going to add 25.7 and 14.2 to get a total of 39.9

Ethan rode 39.9 kilometers.
You might be interested in
What is a perimeter?​
svet-max [94.6K]

Step-by-step explanation:

<h3>A perimeter is either a path that encompasses/surrounds/outlines a shape or its length. The perimeter of a circle or an ellipse is called its circumference. Calculating the perimeter has several practical applications. A calculated perimeter is the length of fence required to surround a yard or garden.</h3>

↓↓↓

<h3>The perimeter is the distance around the object. For example, your house has a fenced yard. The perimeter is the length of the fence. If the yard is 50 ft × 50 ft your fence is 200 ft long.</h3>

#CARETOLEARN

#STAY SAFE!

#STUDYHARD :)

6 0
2 years ago
Read 2 more answers
Marianne has been collecting donations for her biscuit stall at the school summer fayre. There are some luxury gift tins of bisc
LenaWriter [7]
<span>Answer:

Number of luxury gift tins of biscuits sold at £5 each: 18
Number of normal packets sold at £1 each: 2
Number of mini- packs of 2 biscuits sold at 10p each: 80

Solution:

Number of luxury gift tins of biscuits sold at £5 each: x
Amount received by the number of luxury gift tins of biscuits sold: £5 x Number of normal packets sold at £1 each: y
Amount received by the number of normal packets sold: £1 y
Number of mini- packs of 2 biscuits sold at 10p each: z
Amount received by the number of 2 biscuists sold: 10p z =£0.1z

She tells Amy that she has received exactly 100 donations in total:
(1) x+y+z=100

A collective value of £100:
Total amount receibed: £5 x + £1 y+ £0.1z= £100 → £ (5x+1y+0.1z)= £100 → 5x+y+0.1z=100 (2)

Her stock of £1 packets is very low compared with the other items:
y<<x
y<<z
Then we can despice the value of "y" and solve for "x" and "z":
y=0:
(1) x+y+z=100→x+0+z=100→x+z=100 (3)
(2) 5x+y+0.1z=100→5x+0+0.1z=100→5x+0.1z=100 (4)

Solving the system of equations (3) and (4) using the substitution method:
Isolating z in equation (3): Subtrating x from both sides of the equation:
(3) x+z-z=100-x→z=100-x

Replacing z by 100-x in the equation (4):
(4) 5x+0.1z=100→5x+0.1(100-x)=100
Eliminating the parentheses:
5x+0.1(100)-0.1x=100→5x+10-0.1x=100
Adding similar terms on the left side of the equation:
4.9x+10=100
Solving for x: Subtrating 10 from both sides of the equation:
4.9x+10-10=100-10→4.9x=90
Dividing both sides of the equation by 4.9:
4.9x/4.9=90/4.9→x=18.36734693

Replacing x=18.36734693 in the equation:
z=100-x→z=100-18.36734693→z=81.63265306

We can round x and z: x=18 and z=81 and solve for y in equations (1) and (2):
(1) x+y+z=100→18+y+81=100
Adding similar terms on the left side of the equation:
99+y=100
Subtracting 99 from both sides of the equation:
99+y-99=100-99→y=1

(2) 5x+y+0.1z=100→5(18)+y+0.1(81)=100→90+y+8.1=100→98.1+y=100→98.1+y-98.1=100-98.1→y=1.9→y=2 different to 1

Suppose y=1. Replacing y=2 in equations (1) and (2):
(1) x+y+z=100→x+1+z=100→x+1+z-1=100-1→x+z=99
(2) 5x+y+0.1z=100→5x+1+0.1z=100→5x+1+0.1z-1=100-1→5x+0.1z=99

Repeating the process:
z=99-x
5x+0.1z=99→5x+0.1(99-x)=99→5x+9.9-0.1x=99→4.9x+9.9=99→4.9x+9.9-9.9=99-9.9→4.9x=89.1→4.9x/4.9=89.1/4.9→x=18.18367346
z=99-18.18367346→z=80.81632653
x=18 and z=80
(1) x+y+z=100→18+y+80=100→y+98=100→y+98-98=100-98→y=2
(2) 5x+y+0.1z=100→5(18)+y+0.1(80)=100→90+y+8=100→y+98=100→y+98-98=100-98→y=2

Answer:
Number of luxury gift tins of biscuits sold at £5 each: 18
Number of normal packets sold at £1 each: 2
Number of mini- packs of 2 biscuits sold at 10p each: 80 </span>
5 0
3 years ago
Read 2 more answers
A line segment is partitioned with a ratio 2:5, how many total parts has the segment been split into
schepotkina [342]

Answer:

7 parts

Step-by-step explanation:

To get the answer to this, we only simply to know the number of times in which the division was made.

This means that the total ratio of the lines is 2 +5 = 7. Meaning we have 7 different divisions.

The first division carries 2/7 while the second division carrues 5/7

7 0
4 years ago
Simplifying Algebraic Expressions ; 7+9(-6+8)
Grace [21]

Start by multiplying the 9 out:

9(-6 + 8y) = -54 + 72y

Then, add the 7:

-54 + 72y + 7

Then simplify the whole thing:

-47 + 72y

7 0
3 years ago
CAN SOMEONE HELP ME PLS I GIVE POINTS
kogti [31]

Answer:

and i think its b

Step-by-step explanation:

i cnt see the question and its blurry and can i get the crown thing

4 0
2 years ago
Other questions:
  • You randomly sample 5 people in your​ school, and none of them is a vegetarian. Does this mean that the probability of being a v
    13·1 answer
  • According to a recent report, 60% of U.S. college graduates cannot find a full time job in their chosen profession. Assume 57% o
    12·1 answer
  • What is 6 1/8 as a decimal?
    5·2 answers
  • Complete the table for the given rule.<br> Rule: y = 5x
    6·2 answers
  • How many quarters are there in $2?<br> A. 2<br> B. 4 <br> C. 6<br> D. 8
    5·1 answer
  • Consider the quadratic expression given below.
    6·1 answer
  • What is the surface area for the figure, in square centimeters?
    15·1 answer
  • Which table contains ordered pairs that lie on the graph of the equation -2x + 4y = 16?
    10·1 answer
  • 4(d+2)-2(d+4) not sure why I keep getting it wrong
    7·1 answer
  • Each of the 18 students in Mr. Hall's class has
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!