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Luden [163]
3 years ago
5

5 = 7" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0

So for these problems you just need to get all x values on one side of the equal sign. Since this has just an x and not other x values we can leave the x there on the left. Now subtract 5 on both sides to get rid of the 5 on left side of the equals sign. Subtract 5 on the right side too because anything that you do on the left side, you do on the right side as well. It should look like this now:

x+5=7\\ \\ x=7-5\\ \\ x=2

Hope this helps!

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Please help I’ll mark you as brainliest if correct!
WITCHER [35]

Answer:

576 cubic cm

Step-by-step explanation:

l×w×h :) 12 is l , 6 is w, 8 is h !

4 0
3 years ago
(x+3)(x-5)=(x+3)(x−5)=
s344n2d4d5 [400]

Answer:

(x+3)(x-5)=(x+3)(x-5)

      x^2-2  = x^2-2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Marneshia walked three over eight of a mile in three over five of an hour. What equation can be used to calculate her unit rate
Rama09 [41]
3/8 mile in 3/5 hour
\frac{ \frac{3}{8} }{ \frac{3}{5} }
we want to find miles per hour or m/1h
convert 3/5 to 1 by multiplying it by 5/3
keep the fraction the same by multiply ing the whole thing by
\frac{ \frac{5}{3} }{ \frac{5}{3} } to get

\frac{ \frac{15}{24} }{ \frac{15}{15} }=
\frac{ \frac{5}{8} }{ 1}=5/8 miles per hour


7 0
3 years ago
A letter of application is intended to     
Travka [436]
I found the options online. I will state them and provide the answer. 

OPTIONS 
<span>A. find out what the prospective employer has to offer.
B. outline your value to a prospective employer.
C. accompany your portfolio.
D. remind the prospective employer of your recent interview.
</span>
ANSWER.
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8 0
3 years ago
Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
Lorico [155]

Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196

E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg

Lower limit = mean - E = 28.3 0.8 = 27.5 hg

Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg

95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

7 0
4 years ago
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