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Luden [163]
3 years ago
5

5 = 7" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0

So for these problems you just need to get all x values on one side of the equal sign. Since this has just an x and not other x values we can leave the x there on the left. Now subtract 5 on both sides to get rid of the 5 on left side of the equals sign. Subtract 5 on the right side too because anything that you do on the left side, you do on the right side as well. It should look like this now:

x+5=7\\ \\ x=7-5\\ \\ x=2

Hope this helps!

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If the equation of a circle is (x + 4)2 + (y - 6)2 = 25, its center point is
notka56 [123]

Answer:

The second oneis your answer.

6 0
3 years ago
Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2
inna [77]
(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

6 x^{6}/3x = 2 x^{5} \\  \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\

We repeat previous steps until we run out of numbers:
3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2
\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )
6 0
3 years ago
You have 800 square feet of the room reserved for tables
Sav [38]
I hope this helps for question a=16
I hope this helps for question b=12
8 0
3 years ago
Find the measures of EAF DAE and CAD
sdas [7]
You have to build an equation to find the answer,

angles in a straight line add upto 180° 
so your equation would be,

12x+30°=180°
      -30    -30
=12x=150°
   ÷12  ÷12
=x=12.5°

now find the measures of the angles by using 12.5 as x.

angle EAF= 2x
                 =2×12.5
                 =25° degrees

angle DAE= 4x
                 =4×12.5
                 =50°degrees

angle CAD=6x
                 =6×12.5
                 =75°degrees

check,
30+25+50+75=180°degrees

hope this helps.......
7 0
3 years ago
How to find the x ?
KonstantinChe [14]
Does that say 4 x 8x + 1 = 2(squared)x?
3 0
3 years ago
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