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Svet_ta [14]
2 years ago
13

(x+3)(x-5)=(x+3)(x−5)=

Mathematics
2 answers:
MArishka [77]2 years ago
8 0

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Let's solve your equation step-by-step.

( x + 3) ( x - 5) = ( x + 3 ) ( x - 5 ) =

Step 1: Simplify both sides of the equation.

x^2 - 2x - 15 = x^2 - 2x - 15 - x^2\\-2x - 15 = -2x - 15

Step 3: Add 2x to both sides.

-2x - 15 = -2x - 15\\-15 = -15

Step 4: Add 15 to both sides.

-15 + 15 = -15 + 15 \\0 = 0

Answer : All real numbers are solutions.

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

If this helped you, could you maybe give brainliest..?

Also Have a great day/night!

❀*May*❀

s344n2d4d5 [400]2 years ago
3 0

Answer:

(x+3)(x-5)=(x+3)(x-5)

      x^2-2  = x^2-2

Step-by-step explanation:

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A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
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Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

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And the standard deviation of the distribution of the sum of values of X is given by,  

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The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

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The answer is A. 2/3 =5/8

Step-by-step explanation:

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Answer:

2 and 7/8

Step-by-step explanation:

3 + 3/8 - 1/2

3 + 3/8 - 4/8

3 - 1/8

2 and 7/8

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