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AnnyKZ [126]
4 years ago
8

What are the coordinates of the vertices of the image of

Mathematics
2 answers:
Ganezh [65]4 years ago
5 0

Answer:

Option B for both drop-down-menus

Step-by-step explanation:

edge 2020

Umnica [9.8K]4 years ago
3 0

<u>Answer:</u>

W (-1, 4) ---> W' (-4, -1)

X (-1, 2)  ---> X' (-2, -1)

Y (2, 2)  ---> Y' (-2, 2)

Z (2, 4)  ---> Z' (-4, 2)

<u>Step-by-step explanation:</u>

We are given the graph with a rectangular figure WXYZ and we are to find the coordinates of its vertices W'X'Y'Z' after the transformation of 90° rotation.

We know that, the rule for 90° rotation of a point (x, y) gives (-y, x).

So,

W (-1, 4) ---> W' (-4, -1)

X (-1, 2)  ---> X' (-2, -1)

Y (2, 2)  ---> Y' (-2, 2)

Z (2, 4)  ---> Z' (-4, 2)

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What is the area of a circle that has a diameter of 16in
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Answer:

A=πr2

A=π8^2

A=π* 8* 8

A= 64π

A= 64x3.14

A= 200.96 in^2

Step-by-step explanation:

8 0
3 years ago
Joan and Jane are sisters. Jean is Joan's daughter and 12 years younger than her aunt. Joan is twice as old as Jean. Four years
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Jane is 16 twices as old as joan
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3 years ago
The step by step and final answer
Mumz [18]
32. (a) For an even function, f(x) = f(-x). Given f(5) = 3, we know f(-5) = 3.
Therefore (-5, 3) is also on the graph.

For an odd function, f(-x) = -f(x). Given f(5) = 3, we know f(-5) = -3.
Therefore (-5, -3) is also on the graph.

33. f(-x) = -f(x). The function is odd.
34. f(-x) = x/(x-1) ≠ -f(x) ≠ f(x). The function is neither even nor odd.
35. f(-x) = f(x). The function is even.

4 0
3 years ago
Prove 2/sqrt3cosx+sinx=sec(pi/6-x)
dlinn [17]

Thus L.H.S = R.H.S that is 2/√3cosx + sinx  = sec(Π/6-x) is proved

We have to prove that

2/√3cosx + sinx  = sec(Π/6-x)

To prove this we will solve the right-hand side of the equation which is

R.H.S = sec(Π/6-x)

          = 1/cos(Π/6-x)

[As secƟ = 1/cosƟ)

           = 1/[cos Π/6cosx + sin Π/6sinx]

[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]

           = 1/[√3/2cosx + 1/2sinx]

            = 1/(√3cosx + sinx]/2

            = 2/√3cosx + sinx

    R.H.S = L.H.S

Hence 2/√3cosx + sinx  = sec(Π/6-x) is proved

Learn more about trigonometry here : brainly.com/question/7331447

#SPJ9

5 0
1 year ago
Given the function f(x) = - 4x + 2. Find the range using the domain.<br> D:{-1, 2}<br> R:{ , }
Svet_ta [14]

Answer:

R { - 6, 6 }

Step-by-step explanation:

To find the range substitute the values of x from the domain into f(x)

f(- 1) = - 4(- 1) + 2 = 4 + 2 = 6

f(2) = - 4(2) + 2 = - 8 + 2 = - 6

Range { - 6, 6 }

5 0
4 years ago
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