4|x - 1| - 7 = -3 |add 7 to both sides
4|x - 1| = 4 |divide both sides by 4
|x - 1| = 1 ⇔ x - 1 = 1 or x - 1 = -1 |add 1 to both sides
x = 2 or x = 0
Answer: B.
Answer:
5
Cinco es en quince 3 veces igualmentes, 1 vez es uno sobre tres de 15.
Answer:
true
Step-by-step explanation:
B I’m pretty sure it’s that