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Reika [66]
3 years ago
8

What is the place value of the digit 5 in 87.653?

Mathematics
2 answers:
Margarita [4]3 years ago
5 0
the hundredths position
polet [3.4K]3 years ago
3 0

Jiairrac,

The answer is the "hundredths place."

  • The decimal place value would go like this:
  • 8 = tens
  • 7 = ones
  • 6 = tenths
  • 5 = hundredths
  • 3 = thousandths

Which means the digit 5 is in the hundredths place!

Hope this helps!

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One bag of dog food is $32 if I spend a total of $256 how many bags did I buy
Korvikt [17]

Answer:

8 bags

Step-by-step explanation:

256 divide by 32 = 8

5 0
3 years ago
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Simplify the expression:<br> 3j–1+4
RUDIKE [14]

Answer:

3j/3—5/3

J=5/3

hope helps

5 0
3 years ago
Write the percent shown by each model. Explain your reasoning.
Sphinxa [80]
A) 1/3=33 1/3%
B) 2/3=66 2/3%
C) 1/6=16 2/3%

A) YOU CAN TURN THE FRACTION 1/3 INTO A DECIMAL WHICH WILL BE AROUND 0.333. THEN YOU TURN THE DECIMAL INTO A PERCENT. YOU CAN MOVE THE DECIMAL TWO PLACES TO THE RIGHT. THAT GIVES YOU 33.3% OR 33 1/3% THIS ALSO APPLIES TO B BUT WITH 0.666 AND 66.6%

FOR C, YOU DO THE SAME. 1/6 AS A DECIMAL IS 1.666. YOU MOVE THE DECIMAL TWO PLACES TO THE RIGHT. 16.6% OR 16 2/3%


HOPE THIS HELPED.
8 0
3 years ago
What is 1 ten more than 9 ones
Evgesh-ka [11]
19 because 1 ten = 10 ones and 9 one plus 10 ones equals 19 altogether
6 0
3 years ago
For his birthday, Tyrone's parents gave him $7,790.00 which they put into a savings account that earns 15% interest compounded m
torisob [31]

Answer:

5 years and 5 months

Step-by-step explanation:

<u />

<u>Compound Interest Formula</u>

\large \text{$ \sf A=P(1+\frac{r}{n})^{nt} $}

where:

  • A = final amount
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • A = $17,474.00
  • P = $7,790.00
  • r = 15% = 0.15
  • n = 12
  • t = number of years

Substitute the given values into the formula and solve for t:

\implies \sf 17474=7790\left(1+\dfrac{0.15}{12}\right)^{12t}

\implies \sf \dfrac{17474}{7790}=\left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=\ln \left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=12t \ln \left(1.0125}\right)

\implies \sf t=\dfrac{\ln\left(\frac{17474}{7790}\right)}{12 \ln \left(1.0125}\right)}

\implies \sf t=5.419413037...\:years

Therefore, the money was in the account for 5 years and 5 months (to the nearest month).

3 0
2 years ago
Read 2 more answers
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