She will be ready at 7:45 am.
1 1/4 hour = 1 hour and 15 minutes ( 1 hour divided by four is 15 minutes per quarter)
adding that to the initial time of 6:00am you get the time to be 7:15am adding the 1/2 an hour which is 30 minutes. Your final answer is, she will be ready at 7:45am.
Answer:
1
Step-by-step explanation:
because if you do 1 1/2 - 1/2 = 1
The graph behavior of the function that satisfied the conditions given are:
- Horizontal asymptote at y = 0.
- Vertical asymptotes at x = -1 and x = 1.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator, or values of x for which the value of the limit goes to infinity.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity, that is, the limit of f(x) as x goes to infinity.
Hence, for this problem, the graph behavior is given by the following asymptotes:
- Horizontal asymptote at y = 0.
- Vertical asymptotes at x = -1 and x = 1.
More can be learned about asymptotes at brainly.com/question/16948935
#SPJ1
Answer:
6*8=48 groups with elements of order 7
Step-by-step explanation:
For this case the first step is discompose the number 168 in factors like this:
And for this case we can use the Sylow theorems, given by:
Let G a group of order 
where p is a prime number, with 
and p not divide m then:
1) 
2) All sylow p subgroups are conjugate in G
3) Any p subgroup of G is contained in a Sylow p subgroup
4) n(G) =1 mod p
Using these theorems we can see that 7 = 1 (mod7)
By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.
Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.
So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168
Answer:
Step-by-step explanation:
I think you mean a^2 + 16a + 64.
The x-intercepts are the values of a for which the polynomial equals zero.
a^2 + 16a + 64 = (a+8)^2 = 0
a = 8
The x-intercept is 8.
