It is in the air 5.625 seconds.

Using the quadratic formula,

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}
\\
\\=\frac{-90\pm \sqrt{90^2-4(-16)(0)}}{2(-16)}
\\
\\=\frac{-90\pm \sqrt{8100-0}}{-32}
\\
\\=\frac{-90\pm \sqrt{8100}}{-32}=\frac{-90\pm90}{-32}
\\
\\=\frac{-90+90}{-32}\text{ or }\frac{-90-90}{-32}=\frac{0}{32}\text{ or }\frac{-180}{-32}
\\
\\=0\text{ or }5.625$

0 is when the ball is first launched, 5.625 is when it hits the ground again.

4 0

2 years ago

Pam likes to practice dancing while preparing for a math tournament. She spends 80 minutes every day practicing dance and math.

Kisachek [45]

80/2= 20 then take away the extra 20 from the math for dance and you have the answer... 20 get it?

8 0

2 years ago

Read 2 more answers

2x2-3 evaluate each expression. Show your work

nirvana33 [79]

Answer:

Step-by-step explanation:

2x2 = 4

4-3=1

5 0

3 years ago

Work out the value of (2^3)^2​

Work out the value of (2^3)^2