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crimeas [40]
3 years ago
14

There are 4 Board of Directors positions open. 2 will be for men, 2 will be for women.

Mathematics
1 answer:
laiz [17]3 years ago
3 0

Answer:

1980 total outcomes are possible.

Step-by-step explanation:

The order in which the candidates are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many total outcomes are possible?

2 men, from a set of 11.

2 women, from a set of 9.

So

T = C_{11,2}*C_{9,2} = \frac{11!}{2!9!}*\frac{9!}{2!7!} = 1980

1980 total outcomes are possible.

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Negative 3 over 1 third plus 8 over 3 tenths
Katen [24]

The answer to your question is 7/5

3 0
3 years ago
I need to know the answer ASAP
Tomtit [17]

Answer:

2\sqrt{x} is valid for all values of x ≥ 0

Step-by-step explanation:

4 0
2 years ago
If you start with Malvin’s age, take half of it, increase that result by 5, then divide by 3, and finally double that, you get 8
Kisachek [45]

Answer:

24 years old

Step-by-step explanation:

Let Malvin's age be x.

  • x / 2
  • x / 2 + 5 = 5x / 10  [ By taking the L.C.M.]
  • ( 5x / 10 ) * ( 1 / 3 ) = 5x / 30   [ Multiply with the reciprocal of 3 ]
  • ( 5x / 30 ) * 2 = 5x / 15

Now let's solve the equation,

5x / 15 = 8

       5x = 8 * 15

       5x = 120

         x = 120 / 5

         x = 24

Therefore, Malvin is 24 years old.

Hope yo liked the answer!!

If you found it helpful, please mark it as the Brainliest!!

3 0
3 years ago
Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)
mote1985 [20]

For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3  (the sum is multiple of 3 = 3 x 1)  (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2)  (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2)  (213/3 = 71)

27 = 2 + 7 = 9  (the sum is multiple of 3 = 3 x 3)  (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

Learn more about divisibility here: brainly.com/question/9462805

#SPJ1

5 0
2 years ago
Which operation should you perform first when you simplify the expression below? 10 ÷ 2 + 3(8 × 9)= A addition B subtraction C m
N76 [4]
C. multiplication (the 8 x 9 within the parenthesis)
8 0
3 years ago
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