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VARVARA [1.3K]
4 years ago
10

Use the zero product property to find the solutions to the equation x2 – 13x + 30 = 0.

Mathematics
2 answers:
babunello [35]4 years ago
6 0

Answer:

x=3 and x=10

Step-by-step explanation:

The given equation is:

x^2-13x+30=0

Upon solving the above equation, we get

⇒x^2-10x-3x+30=0

⇒x(x-10)-3(x-10)=0

⇒(x-3)(x-10)=0

Now, using the zero product property, we get

x-3=0 and x-10=0

⇒x=3 and x=10

which are the required values of x.

Len [333]4 years ago
5 0
X=3 or x=10 hope this helps! ;p
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You have won the lottery and will receive 20 annual payments of $10,000 starting today. If you can invest these payments at 8.5%
xxTIMURxx [149]

Answer:

$102,677.20

Step-by-step explanation:

The present value of an annuity due is determined by the following expression:

PV = P+P*(\frac{1-(1+r)^{-n+1}}{r})

Where 'P' is the amount of each payment received, 'r' is the interest rate on the investment and 'n' is the number of yearly payments.

With 20 annual payments of $10,000 at a rate of 8.5%, the present value is:

PV = 10,000+10,000*(\frac{1-(1+0.085)^{-20+1}}{0.085})\\PV = 10,000+ 10,000*(9.26772)\\PV=\$102,677.20

The present value of your winnings is $102,677.20.

8 0
3 years ago
Solve:<br><br>1/5c =15<br><br>c=__<br>solve what c equals
grin007 [14]

Answer:

75

Step-by-step explanation:

a fifth of c is 15

75÷5=15

4 0
4 years ago
A piece of machinery depreciates $5000 the first year,
eimsori [14]

Answer:

A- $3500

Step-by-step explanation:

The depreciation rate is $300

$5000, $4700, $4400

$300 x 3 = 900

$4400 - 900 =

$3500.

4 0
3 years ago
Please answer! I crossed out the ones you don’t have to complete.
Nina [5.8K]

Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

a.a as a^{1+1}=a^2

b.b.b.b as: b^{1+1+1+1}=b^4

So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

The rule used here will be: a^{-1}=\frac{1}{a^1} which states that if we need to make exponent positive, we will take it to the denominator.

Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

6) 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

4 0
3 years ago
Help me find x please!
lana [24]
X should equal 100.  Hope this helps :)
4 0
3 years ago
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