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bogdanovich [222]

3 years ago

12

A one dollar coin, a two dollar coin and a six sided dice are tossed. how many results are possible?

2 answers:

bonufazy [111]3 years ago

8 0

<span>24. The number of results is simply the product of the number of possibilities for each object tossed. Each coin may lands heads up, or tails up, for 2 possibilities each. And the die may land with 6 possible faces up. So the number of possibilities is 2 * 2 * 6 = 24. So the total number of possible results is 24.</span>

Nimfa-mama [501]3 years ago

7 0

Answer:

10

Step-by-step explanation:

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Julli [10]

Answer:

"0.0373" seems to be the appropriate solution.

Step-by-step explanation:

The given values are:

n₁ = 43

n₂ = 35

$\bar{x_1}=217800$

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$\sigma_1=30300$

$\sigma_2=33800$

Now,

The test statistic will be:

⇒ $Z=\frac{\bar{x_1}-\bar{x_2}}\sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }$

On substituting the given values in the above formula, we get

⇒ $=\frac{217800-204400}{\sqrt{\frac{(30300)^2}{43} +\frac{(33800)^2}{35} } }$

⇒ $=\frac{217800-204400}{\sqrt{\frac{918090000}{43} +\frac{1142440000}{35} } }$

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