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katrin [286]
3 years ago
11

Which of the following points represents the center of a circle whose

Mathematics
2 answers:
nadezda [96]3 years ago
6 0

Answer:

compare with the equation of the circle (x-a)^2 + (y -b )^2 = r^2

(a,b) are the centers of the circle

therefore, the centers are (5,4)

Step-by-step explanation:

jarptica [38.1K]3 years ago
5 0

Answer:

D

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r the radius

(x - 5)² + (y - 4)² = 25 ← is in standard form

with centre = (5, 4) → D

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If ax2 + bx + c = 0, then x= ? (Hint: Quadratic Formula)
Finger [1]

Answer:

x = ± \sqrt{\frac{b^{2} -4ac}{2a}

It didn't insert but just look up the quadratic formula.  

x = ± root [(b²-4ac]/2a]

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3 years ago
A real estate agent has 8 master keys to open several new homes. Only 1 master key will open any given house. If 40% of these ho
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Answer:

Step-by-step explanation:

Suppose F represents the value that a room is unlocked.

Then, we can assume that the probability of unlocked homes is:

P(unlocked homes) = P(U)

P(unlocked homes) = 40%

P(unlocked homes) = 0.40

Also, let us represent the value of the locked room with G.

P(locked homes) = P(G)

P(locked homes) = (1 - 0.40)

P(locked homes) = 0.60

Let the probability of selecting a correct key be P(S)

It implies that for the agent to use 3 keys, we have a combination of ^8C_3 possible ways for the set of keys.

Now; since only one will open the house, then:

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P(S) = \dfrac{21}{56}

P(S) = 0.375

Finally, for the real estate agent to have access to specific homes supposing the agent select three master keys at random prior to the time he left his office, Then:

P(F ∪ (G∩S) = P(F) + P(G∩S)

P(F ∪ (G∩S) = P(F) + P(G) × P(S)

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2 years ago
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4.5

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Since they share the same proportions, the same operations can be performed on each base to find the area.

The answer can be found with the knowledge that the area of a triangle is half of the height * width. You know the width of ∠BAC is 4, and the area is 8, so 16 (the area doubled) / 4 is the height. The width and height of ∠BAC are the same, and since the proportions are also the same, the width and height of ∠EDF are both 3. So the area is the width (3) times the height (3) divided by 2.

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6 0
3 years ago
Answer step by step
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Consider, please, this solution/explanation:
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