Answer: The total number of logs in the pile is 6.
Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.
We are to find the total number of logs in the pile.
Let n represents the total number of logs in the pile.
Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with
first term, a = 32 and common difference, d = -6.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is
Since there are n logs in the pile, so we get
Thus, the total number of logs in the pile is 6.
Answer:
y = 3
Step-by-step explanation:
2x-3y = -5 --------- (1)
y = 2+x ------- (2)
substitute (2) into (1)
2x-3y = -5
2x-3( 2+x ) = -5
2x-6-x = -5
2x-x = -5+6
x = 1
substitute x = 1 into (2)
y = 2+x
y = 2+1
y = 3
Answer:
The product of 3 and 4 plus the quotient of 6 and 2 (aka the second one)
Step-by-step explanation:
15 percent of 760 is 114
760 - 114 = 646
Hope this helps :D
The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins
The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L
