8% of 44 show work please and an answer ciz i domt understand

1 answer:

7 0

Hey there!

These are the steps involved in answering the question:

Change 8% into a decimal. To do this, just move the decimal place, 2 places to the left.
You get 0.8

Now, multiply 0.8 by 44.
0.8 x 44 = 35.2

So, the final answer is: 35.2.

(If you feel that my answer has helped you, please consider rating it and giving it a thank you! Also, feel free to choose the best answer, the brainliest answer!)

Thank you for being part of the brainly community! :D

You might be interested in

Please help with this question

barxatty [35]

slope=y2 - y1

x2 - x1

= -1 - -3

-7 - -9

= -2

-2

= 1

I think the answer is D

3 0

3 years ago

What are the solutions to the equation x - (7/x) = 6

BlackZzzverrR [31]

Answer: c. x=-1 and x=7

Step-by-step explanation:

7 0

4 years ago

In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha

siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$