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nirvana33 [79]
3 years ago
10

Si X es una variable aleatoria de tipo continuo… ¿Es posible definir el índice de asimetría de Fisher? ¿Por qué?

Mathematics
1 answer:
Nana76 [90]3 years ago
8 0

Answer:

Primero, para un caso discreto, el índice de asimetría de Fisher se calcula como:

\frac{\sum(xi - M)*n_i}{N*S_x}

Donde:

xi son los i-esimos distintos valores de nuestro conjunto de datos.

M es la media

N es el numero de datos

ni es la frequencia absoluta de cada xi

Sx es la desviacion tipica

Podemos ver que en el caso discreto, escribimos el coeficiente con una sumatoria, lo cual realmente no podemos hacer para una variable continua.

Lo que si podemos hacer para una variable continua, es una integral, donde como esta vez tenemos una variable continua, podemos definir una función:

f(X) = frequencia absoluta para X.

Y escribir el coeficiente como:

\frac{\int\limits^a_b {(X - M)*f(x)} \, dx }{N*S_x}

Entonces si, es posible definir el índice.

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Answer:

  11 73/78 ≈ 11.9359   (not 14)

Step-by-step explanation:

The similarity statement tells us ...

  QS/QR = FG/FH

  QS = QR·FG/FH

  13x -14 = 154(55/60) = 847/6

Adding 14 = 84/6, we have ...

  13x = 931/6

  x = 931/78 = 11 73/78 . . . . . . . divide by 13

__

<em>Comment on the question</em>

You get a nice integer answer for x if the similarity statement is written ...

  ∆FGH ~ ∆QRS . . . . . . . note the letters are in alphabetical order

Then you have ...

  QS/QR = FH/FG

  13x -14 = 154(60/55) = 168

  13x = 182

  x = 14

This nice answer to a nice similarity statement leads us to believe the question has an error in it.

We suspect you are expected to provide x=14 as the answer, even though that is NOT the answer to the question <em>as written</em>. You may want to discuss this with your teacher.

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D is the problem child. Nothing I can think of right now will not change will you add 1 to it. If you can think of something that doesn't change when you add one to it, please put it in the comments. Otherwise, D is not an identity.

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