Answer: 
Step-by-step explanation:





Answer:
2(4 + X)
2*4 + 2*X
8+2X
thank you
Step-by-step explanation:
hope my answer is helpful to you
H is the answer
and the line of the symmetry is like the picture
Answer:
<em>Camera 2nd has to cover the maximum angle, i.e. </em>
.
Step-by-step explanation:
Please have a look at the triangular park represented as a triangle
with sides
a = 110 ft
b = 158 ft
c = 137 ft
1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.
We can use law of cosines here, to find out the angles 
As per Law of cosine:

Putting the values of a,b and c to find out angles
.



<em>Camera 2nd has to cover the maximum angle</em>, i.e.
.
Scale factor = 0.5 / 25 = 0.02 inches per foot
on scale drawing of the park the dimensuons will be 600 * 0.02 by 1000*0.02
= 12 inches by 20 inches