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il63 [147K]
3 years ago
11

The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either

from Rome, Italy or New York, New York:
           High   Low   Q1     Q3    IQR   Median    Mean        σ
Rome 18         1        3       7       4         6.5       6.4           4.3
NY      14        1       4.5    8.5      4        5.5        6.1            3.2

Which of the choices below best describes how to measure the center of this data?

- Both centers are best described with the mean.

-Both centers are best described with the median.

- The Rome data center is best described by the mean. The New York data center is best described by the median.

-The Rome data center is best described by the median. The New York data center is best described by the mean.
Mathematics
2 answers:
Harrizon [31]3 years ago
5 0

Answer:  D. The Rome data center is best described by the median. The New York data center is best described by the mean.

I just completed the test and this is the correct answer. I apologize for no step by step explanation.

Gala2k [10]3 years ago
3 0

To solve this problem, let us first define what is mean and median. Mean is the average of all the numbers in the data set while the median is the number in the middle of the data set in ascending order.

If we create a box plot for the data of Rome and New York, we can see that there is an outlier in the data for New York. Since New York has an outlier, so the mean is not a good representation on the central tendency of the data. The mean is skewed (distorted) by the outlier. So in this case it is better to use the median.<span>

While the Rome data is nice and symmetrical, it does not seem to have an outlier,  so we can use the mean for this data set.</span>

 

Therefore the answer is:

<span>The Rome data center is best described by the mean. The New York data center is best described by the median</span>

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A standard six-sided die is rolled twice and the top faces are observed. What is the probability that the sum of the numbers on
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<u>Answer: </u>

A standard six-sided die is rolled twice and the top faces are observed and the probability that the sum of the numbers on the top faces is 10 is \frac{1}{12}

<u>Solution: </u>

The sample space of two dice outcomes is given as follows:

{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3, 1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4, 1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5, 1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6, 1) (6,2) (6,3) (6,4) (6,5) (6,6) }

Total number of events n(s) = 36

Expected Outcomes = {(4, 6), (5, 5), (6, 4)}

Number of favorable outcomes n(E) = 3

Probability (sum of numbers on the top faces is 10) = \frac{n(E)}{n(s)} = \frac{3}{36} = \frac{1}{12}

Therefore the probability that the sum of the numbers on the top faces is 10 is \frac{1}{12}

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