System of equation x 3y=9 y=x-1

Divide the polynomials (x^3-x^2-11x+15)/(x-3)

nasty-shy [4]

The answer to this is x^2 + 2x - 5

4 0

2 years ago

These are the values in Greta’s data set. (2, 43), (3, 46), (4,61), (6, 70), (7,74) Greta determined the equation of a linear re

JulijaS [17]

Answer: See the description below.

The residuals are the difference between the actual and predicted values. Just subtract those values and plot the point.

Your points will be:

(2, 0)
(3, 4)
(4, -5)
(6, -1)
(7, 2)

8 0

2 years ago

You are dealt one card from a 52 card deck. Then the card is replaced in the deck, the deck is shuffled, and you draw again. Fin

AlladinOne [14]

Answer:

3/52

Step-by-step explanation:

The picture card are j,q k and there are 4 of each so there are 12 picture cards

P( picture card) = picture card/ total

12/52 = 3/13

Then replace the card

There are 13 clubs

P( club) = club/ total

13/52 = 1/4

P(picture,replace,club) = 3/13*1/4 = 3/52

7 0

2 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

2 years ago

Serial numbers for a product are to be made using 2 letters followed by 3 digits the letters are to be taken from the first 6 le

kipiarov [429]

Answer:

Step-by-step explanation:

We have to make 5 place serial number with first two as alphabets and last three as digits.

The alphabets are bonded to first 6 ( A, B, C, D, E, F) where as digits are 10 (say 1 to 10).

Let the serial number be S1 S2 S3 S4 S5.

For Alphabets

For S1 we have 6 alphabets.

Now for S2 we are left with 5 alphabets since there is no repetition one alphabet will be fix for S1.

So the possible combination for S1 S2= 6x5=30.

For Digits

We did the same as we did for alphabets, for S3 we have 10 possibilities, and for S4 and S5 9 and 8 respectively due to the no repetition condition.

So the possible combinations for S3 S4 S5 = 10x9x8=720

So the total number of serial numbers are 30+720=750.

7 0

2 years ago