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3 years ago

Can someone help me get the answer but elimination please!!

Mathematics

1 answer:

pantera1 [17]3 years ago

7 0

Y = 5x - 2
9y = -2x + 10

9y = 3x + 8

y = (3/9)x + 8/9

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Choose the answer that best translates the algebraic expressic<br> 6(w+2)<br> KATES MATH LESSONS

____ [38]

Answer: where is it?

what do u mean??? im confused...

7 0

3 years ago

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

$\sum_{n=1}^{inf}\frac{1}{n^p}$

if p>1 then series converges. In oue case we have:

$\sum_{n=1}^{inf}b_n=\frac{1}{n^4}$

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

5 0

3 years ago

Solve the equation log^7b>2

ahrayia [7]

Answer:

b > 12.71

Step-by-step explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is $(\log b)^{7} > 2$

⇒ $\log b > 2^{\frac{1}{7} }$

We are taking the base of the log here is 10.

So, $10^{(\log b)} > 10^{2^{\frac{1}{7} } }$ {Since $10^{\log x} =x$ and $e^{\ln x} = x$ }

⇒ b > 12.71 (Approximate) (Answer)

3 0

3 years ago

a rectangular jewelry box cost $125 to gold plate. calculate the cost of gold plating a box which is similar in shape and that h

Wewaii [24]

The cost of plating a rectangular jewelry box is $125, the cost of plating a similar box that is 8 times the size will be given by:
Cost=(scale factor)*(price)
Cost=125×8
Cost=$1000
Answer:$1000

3 0

3 years ago

The dimensions of an office conference room or 8' x 16' if the conference room blueprint dimensions are 4 cm x 8 cm what is the

Olegator [25]

The scale is 1 cm per 2 ft

3 0

3 years ago