I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
You get the expression;
3H-21
Hope this helps.
Answer: 3 , 76
Step-by-step explanation:
Khan Academy
I just took it i hope it helps give some feedback tnx.
I think the answer might be 6p^2+3p-63
Answer:
x = -4y/7 + 51/7
Step-by-step explanation:
First, you add all the numbers without variables and are on the same side.
7x - 4 + 4y + 8 = 55
Then you do the opposite sign (for example the opposite of addition is subtraction) of the two numbers without variables on the left side to add them to the right side(what you do on one side of the equation you must do on the other.
4x - 4 + 4 + 4y + 8 - 8 = 55 + 4 - 8
4x + 4y = 51
Then you get the x by itself by doing the same thing you did with the last step by this time with 4y. Because this has a variable, you don't add it onto the 51, but add as a different number.
4x + 4y - 4y = 51 - 4y
4x = -4y + 51
Now to isolate the x, you divide 4x by 4.
4x/4 = -4y/7 + 51/7
x = -4y/7 + 51/7
Your answer is x = -4y/7 + 51/7
