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3 years ago

What is the lowest common multiple (LCM) of 8, 2 and 5?

Mathematics

2 answers:

aivan3 [116]3 years ago

8 0

Answer:

Step-by-step explanation:

Using the method of prime factors

8 = 2 × 2 × 2 = 2³

2 = 2

5 = 5

Then LCM = 2³ × 5 = 8 × 5 = 40

olga2289 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

The goal of LCM is to get the least common number that can divide any of the numbers given without turning them into fractions until all of them are divided to 1.

The least number that can divide any of the numbers is 2, dividing through we remain with 8/2=4, 2/2=1, and 5. Notice how the 5 remains the same, since dividing it by 2 will turn it into a fraction

Divide through by 2 again, we get 4/2=2, 1, and 5

Divide through by 2 yet again, we get 2/2=1, 1, and 5

Divide through by 5, we get 1, 1, and 1

The LCM is now multiplications of all the least numbers used above= 2*2*2*5=40

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A cable weighing 0.6 pounds per foot is attached to a small 80-pound robot, and then the robot is lowered into a 60-foot deep we

ollegr [7]

Answer:6060 foot-pounds

Step-by-step explanation:

Given

Weight of cable(w')=0.6 pound per foot

depth of well=60 foot

weight of wrench=7 Pound

Now work done in raising monkey with wrench $=w\cdot h$

$W_1=(80+7)\cdot 60=5220$ foot-pounds

Now work done in raising rope

robot rises by climbing up the cable with one end of the cable still attached thus robot support half the weight of cable so work done

$W_2==\int_{0}^{60}\frac{w'}{2}xdx$

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$W_2=540$ foot-pounds

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2 years ago

The state of Kansas has a sales tax of 5.3%, and the maximum rate a consumer can pay for local sales tax is 8.65%. What is the r

zvonat [6]

On the face of it, [5.3%, 8.65%].

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3 years ago

Read 2 more answers

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ycow [4]

Answer:

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3 years ago

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larisa [96]

Answer:

As $Z$ , it is possible to reject null hypotesis. It means that the local mean height is less tha 0.7 m with a 5% level of significance.

Step-by-step explanation:

1. Relevant data:

$\mu=0.70\\N=40\\\alpha=0.05\\X=0.65\\s=0.20$

2. Hypotesis testing

$H_{0}=\mu=0.70$

$H_{1} =\mu< 0.70$

3. Find the rejection area

From the one tail standard normal chart, whe have Z-value for $\alpha=0.05$ is 1.56

Then rejection area is left 1.56 in normal curve.

4. Find the test statistic:

$Z=\frac{X-\mu_{0} }{\sigma/\sqrt{n}}$

$Z=\frac{0.65-0.70}{0.20/\sqrt{40}}\\Z=-1.58$

5. Hypotesis Testing

$Z_{\alpha}=1.56\\Z=-1.58$

$-1.58$

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3 years ago

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DanielleElmas [232]

Hi. The statement you gave is somewhat true, but not always. I disprove this and there are tons of websites that can help you with more in depth explanation. Have a good day.

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