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kaheart [24]
3 years ago
9

.    。    •   ゚  。   .    .      .     。   。 .   .   。      ඞ 。 .    •     •   ゚   villain deku was An Impostor.  。 .   '    1 I

mpostor remains     。   ゚   .   . ,    .  .
bakugo
ඞ​
Mathematics
2 answers:
Pie3 years ago
3 0

Answer:

Step-by-step explanation:

:o who is it?!?!?!

andrew11 [14]3 years ago
3 0

Answer:

RAWR and nice among us thing

Step-by-step explanation:

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Pls help I’ll brainlest
Marianna [84]

Answer:

Step-by-step explanation:

Mistakes: The student did not distribute the 3 into 2, and the student did not distribute the 6 into negative 2. The student also left out the negative 2x in the first half of the equation.

6 0
2 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!!
Rus_ich [418]

Answer:

y= -2x -4

Step-by-step explanation:

slope: rise/run = 2/-1 = -2

y-intercept: -4

5 0
2 years ago
Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
3 years ago
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PLEASE HELP! DUE SOON!!!!
yKpoI14uk [10]

Answer: yes

Step-by-step explanation:

4 0
2 years ago
How many more hostel rooms have 4 to 7 guests than 20 to 23 guests?
Ksenya-84 [330]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
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