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3 years ago

Order from least to greatest 1/8, 7/8, 4/8

Mathematics

2 answers:

atroni [7]3 years ago

8 0

first 1/8 then 4/8 and lastly 7/8

Naddika [18.5K]3 years ago

5 0

Answer:

1/8 = 0.125

7/8 = 0.875

4/8 = 0.5

The order from least to greatest is :

1/8, 4/8, 7/8

Step-by-step explanation:

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Please help me with this question

Olegator [25]

Answer:

x = 11

Step-by-step explanation:

Since we are given triangle PQR is similar to triangle PTU, we can write a proportion to connect the side lengths:

PQ / PT = QR / TU = PR / PU

We don't really care about QR and TU because the are irrelevant to the problem, so we can remove them:

PQ / PT = PR / PU

Now, we can substitute the values given by the diagram:

70 / 30 = 49 / (x + 10)

We can cross multiply,

70(x + 10) = 30 * 49

And divide by 70 on both sides(too lazy to multiply :P)

x + 10 = 3 * 7

x + 10 = 21

x = 11

5 0

3 years ago

Write the standard form of the equation of the circle with the given characteristics. Center: (3, 5); Solution point: (−2, 17)

Angelina_Jolie [31]

$\text{we know that the general equation of the circle is }\\
\\
(x-h)^2+(y-k)^2=r^2\\
\\
\text{where, (h,k) is the center of the circle and r is the radius.}\\
\\
\text{Given that the centered of the circle is at }(h,k)=(3,5)\\
\text{and a solution point on circle is (-2,17).}\\
\\
\text{so the radius of the circle will be the distance between center and the }$

$\text{solution point. so using the distance formula, we have}\\
\\
\text{Radius, }r=\sqrt{(-2-3)^2+(17-5)^2}\\
\\
\Rightarrow r=\sqrt{25+144}\\
\\
\Rightarrow r=\sqrt{169}\\
\\
\Rightarrow r=13\\
\\
\text{Hence using the standard for of circle, equation of circle with center}\\
(h,k)=(3,5) \text{ and radius r=13 is}\\
\\
(x-3)^2+(y-5)^2=(13)^2\\
\\
\Rightarrow (x-3)^2+(y-5)^2=169$

3 0

3 years ago

The line has the same slope as 7x-y=5 and the same y intercept as the graph 3y-11x=15

scoundrel [369]

7x - y= -5. Standard form is when it is written with x and y on the same side, but x is not negative or a fraction. To find the slope and y intercept, you must change the first two equations to slope intercept. You get y=7x-5 for the first one and y=11/3x+5 for the seccond equation. Take the 5 as your y intercept and the 7 as your slope and you get y=7x+5. Now you need to change it into standard form. When all is said and done, your final answer should be 7x - y = -5.

4 0

3 years ago

Read 2 more answers

A circle is centered at J(3, 3) and has a radius of 12.

stealth61 [152]

Answer:

$(-6,\, -5)$ is outside the circle of radius of $12$ centered at $(3,\, 3)$ .

Step-by-step explanation:

Let $J$ and $r$ denote the center and the radius of this circle, respectively. Let $F$ be a point in the plane.

Let $d(J,\, F)$ denote the Euclidean distance between point $J$ and point $F$ .

In other words, if $J$ is at $(x_j,\, y_j)$ while $F$ is at $(x_f,\, y_f)$ , then $\displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}$ .

Point $F$ would be inside this circle if $d(J,\, F) < r$ . (In other words, the distance between $F\!$ and the center of this circle is smaller than the radius of this circle.)

Point $F$ would be on this circle if $d(J,\, F) = r$ . (In other words, the distance between $F\!$ and the center of this circle is exactly equal to the radius of this circle.)

Point $F$ would be outside this circle if $d(J,\, F) > r$ . (In other words, the distance between $F\!$ and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between $J$ and $F$ :

$\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145} \end{aligned}$ .

On the other hand, notice that the radius of this circle, $r = 12 = \sqrt{144}$ , is smaller than $d(J,\, F)$ . Therefore, point $F$ would be outside this circle.

5 0

3 years ago

Find the derivative of the function f(x)2x^4+x^3-x^2+4

eduard

Answer:

Step-by-step explanation:

can i pls have brainliest??

3 0

3 years ago