Can you please help?

What is the maximum number of possible extreme values for the function,<br> f(x) = х2 -7x – 6?

timama [110]

Answer:

Only one extreme value of f(x) is possible.

Step-by-step explanation:

We are given the quadratic function of independent variable x which is f(x) = x² - 7x - 6 ......(1)

Now. the condition for extreme values of f(x) is $\frac{df(x)}{dx} =0$

Hence, differentiating both sides of equation (1) with respect to x, we get

$\frac{df(x)}{dx} = 2x -7$ = 0

⇒ x = 3.5.

So there is only one value of x for which f(x) has extreme value which is x = 3.5.

Therefore, only one extreme value of the given function is possible. (Answer)

3 0

3 years ago

2. An expression is shown.

laiz [17]

Adding parentheses in the component $9\div 3$ of the expression may bring an output of 48.

<h3>Procedure - Application of hierarchy rules in a arithmetic expression</h3>

In this question we should make use of hierarchy rules represented by the use of parentheses. The parentheses oblige to make operations inside it before making it in the rest of the formula.

Now we decide to add parenthesis in the component $9\div 3$ such that the result of the entire expression is 48. We proceed to present the proof:

$2 \times 8 \times (9\div 3)$

$2\times 8 \times 3$

$2\times 24$

$48$

Adding parentheses in the component $9\div 3$ of the expression may bring an output of 48. $\blacksquare$

<h3>Remarks</h3>

The statement presents mistakes and is poorly formatted. Correct form is shown below:

An expression is shown: $2\times 8 \times 9 \div 3$

Using the same expression, add parenthesis so that the value of the expression is 48.

To learn more on hierarchy rule, we kindly invite to check this verified question: brainly.com/question/3572440

5 0

2 years ago

Let AA and BB be events such that P(A∩B)=1/73P(A∩B)=1/73, P(A~)=68/73P(A~)=68/73, P(B)=21/73P(B)=21/73. What is the probability

krok68 [10]

Answer:

$P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}$

Step-by-step explanation:

Let A and B events. We have defined the probabilities for some events:

$P(A') =\frac{68}{73} , P(B) =\frac{21}{73} , P(A \cap B) =\frac{1}{73}$

Where A' represent the complement for the event A

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: $P(A)+P(A') =1$