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Katyanochek1 [597]
3 years ago
10

The line plot shows the heights of the basketball players on Team A. Suppose the 4 shortest players on Team B have the same comb

ined height as the 4 shortest players on Team A, but the 4 shortest players on Team B are all the same height. Which is their height?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

72.5

Step-by-step explanation:

The plot shows the height of Team A players, so the 4 shortest one will be 69, 73, 74, 74

The combined height of the 4 shortest Team A player will be: 69+73+74+74= 290

The 4 shortest players on Team B also has the same combined height as the Team A. All of the 4 shortest players on Team B also have the same height, so to find the individual height you just need to divide the combined height(290) with the total player(4). The height of the shortest Team B player will be: 290/4 = 72.5

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<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\

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The first ten terms of the sequence a_n=1 + (-\frac{4}{9} )^n is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

Find out more on equation at: brainly.com/question/2972832

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