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Phoenix [80]
3 years ago
15

8. Which expression is greatest? Justify your answer. a. 4 X -5 b. -5 + 4 c. -4- (-5)

Mathematics
2 answers:
irga5000 [103]3 years ago
5 0
1 is the correct answer
vladimir1956 [14]3 years ago
3 0

Answer:

c

Step-by-step explanation:

i think this is the greatest because if you solve all of the expressions you will find out that this is the greatest.

a.4×-5=-20

b.-5+4=-1

c.-4-(-5)=1

therefore 1 is the greatest so the expression c is the greatest.

I hope this helps

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Which of the following best describes the relationship between the variables on the scatter plot below?
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Answer:

A. negative correlation

Step-by-step explanation:

Let two variables x and y, the correlation coefficient r measure to what degree the variables x and y are related.

--- If this coefficient is positive then the relationship will be positive. This means that even an increase in the variable x will produce an increase in the variable y. In the dispersion diagram the points will be grouped, simulating a line of positive slope.

--- If this coefficient is negative then the relation will be negative. This means that even an increase in the variable x will produce a decrease in the variable y. In the dispersion diagram the points will be grouped, simulating a negative slope line.

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3 years ago
Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to
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The  confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

  The  sample size is n = 41

   

For a 95% confidence the level of significance is  \alpha  = [100 - 95]\% =  0.05 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }=  1.96

For a 90% confidence the level of significance is  \alpha  = [100 - 90]\% =  0.10 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }=  1.645

So we see with decreasing confidence level the critical value  decrease

Now the margin of error is mathematically represented as

         E =  Z_{\frac{\alpha }{2} } *  \frac{s}{\sqrt{n} }

given that other values are constant and only Z_{\frac{\alpha }{2} } is varying we have that

         E\ \  \alpha \ \   Z_{\frac{\alpha }{2} }

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  The  confidence interval is mathematically represented as

        \= x  - E  <  \mu <  \= x  + E

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