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3 years ago

15

When you calculate the sample size for a proportion, you use an estimate for the population proportion; namely . A conservative

value for n can be obtained by using = ______ .
A.0.50
B.0.05
C.0.10
D.0.01

1 answer:

LuckyWell [14K]3 years ago

5 0

Answer: A. 0.50

Step-by-step explanation:

The formula to find the sample size : $n=p(1-p)(\dfrac{ z^*}{E})$

, where p= Prior estimate of population proportion.

E= Margin of error

z* =Critical z-value.

When , we do not have prior estimate of population proportion , we use p= 0.5 because at p=0.5 it gives the maximum same sample size for the corresponding confidence interval and margin of error.

Therefore , the conservative value for n can be obtained by using p=0.50.

Therefore , the correct answer is A.0.50 .

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we have

$4(x + 3) \leq 0$ -------> inequality 1

or

$x + 1 > 3$ -------> inequality 2

we know that

In this system of inequalities, for a value to be the solution of the system, it is enough that it satisfies at least one of the two inequalities.

let's check each of the values

<u>case 1)</u> x=-6

<u>Substitute the value of x=-6 in the inequality 1</u>

$4(-6 + 3) \leq 0$

$4(-3) \leq 0$

$-12 \leq 0$ -------> is ok

The value of x=-6 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

<u>case 2)</u> x=-3

<u>Substitute the value of x=-3 in the inequality 1</u>

$4(-3 + 3) \leq 0$

$4(0) \leq 0$

$0 \leq 0$ -------> is ok

The value of x=-3 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

<u>case 3)</u> x=0

<u>Substitute the value of x=0 in the inequality 1</u>

$4(0 + 3) \leq 0$

$4(3) \leq 0$

$12 \leq 0$ -------> is not ok

<u>Substitute the value of x=0 in the inequality 2</u>

$0 + 1 > 3$

$1 > 3$ --------> is not ok

The value of x=0 is not a solution of the compound inequality

case 4) x=3

<u>Substitute the value of x=3 in the inequality 1</u>

$4(3 + 3) \leq 0$

$4(6) \leq 0$

$24 \leq 0$ -------> is not ok

<u>Substitute the value of x=3 in the inequality 2</u>

$3 + 1 > 3$

$4 > 3$ --------> is ok

The value of x=3 is a solution of the compound inequality

case 5) x=8

<u>Substitute the value of x=8 in the inequality 1</u>

$4(8 + 3) \leq 0$

$4(11) \leq 0$

$44 \leq 0$ -------> is not ok

<u>Substitute the value of x=8 in the inequality 2</u>

$8 + 1 > 3$

$9 > 3$ --------> is ok

The value of x=8 is a solution of the compound inequality

<u>case 6)</u> x=10

<u>Substitute the value of x=10 in the inequality 1</u>

$4(10 + 3) \leq 0$

$4(13) \leq 0$

$52 \leq 0$ -------> is not ok

<u>Substitute the value of x=10 in the inequality 2</u>

$10+ 1 > 3$

$11 > 3$ --------> is ok

The value of x=10 is a solution of the compound inequality

therefore

<u>the answer is</u>

[-6,-3,3,8,10]

7 0

3 years ago