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Anestetic [448]
3 years ago
7

PLEASE HELP ASAP 20 POINTS!!!

Mathematics
1 answer:
Olenka [21]3 years ago
7 0
Function 1 is a constant function
.. y = 2

Function 2 has the value 3 at x=0.

3 is greater than 2, so Function 2 has the greater initial value.
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Type the correct answer in the box. Use numerals instead of words.
Vladimir79 [104]

Using the surface area of the sphere, it is found that the radius of the bearing that Helen needs to buy is of 6 millimeters.

<h3>What is the surface area of a sphere?</h3>

The surface area of a sphere of radius r is given by:

S_A = 4\pi r^2

In this problem, we have that:

S_A = 452.16

Hence:

4\pi r^2 = 452.16

r = \sqrt{\frac{452.16}{4\pi}}

r = 6.

The radius of the bearing that Helen needs to buy is of 6 millimeters.

More can be learned about the surface area of a sphere at brainly.com/question/21207980

#SPJ1

5 0
2 years ago
Which of the following shows the correct order?
satela [25.4K]

Answer:

The last one, (1/2)^2 < 2/3 < 0.75

Step-by-step explanation:

So lets try to put each number in the same form, and see what their values are.

Lets start with (1/2)^2

This is squaring the 1 and 2 in 1/2. 1^2 is 1. 2^2 is 4. So its now:

1/4

Lets look at the others:

2/3

Lets just give it a common denominator. To do this, lets find the lowest number that both 3(from 2/3) and 4(from 1/4) go into. This is also known as the LCM.

This will be 12.

Since 3(from 2/3) goes into 12 4 times, we multipy both numerator and denominator of 2/3 by 4:

4*2=8, 3*4=12:

8/12

Since 4(from 1/4) goes into 12 3 times, we multiply both the numerator and denominator by 3:

1*3=3, 4*3=12:

3/12

So lets just go over what we know so far:

(1/2)^2 = 3/12

2/3 = 8/12

Now lets find our last value:

0.75

When converted into fraction form, we will get:

3/4

We already have a LCM, which is 12, that goes into this.

The denominator goes into 12 3 times, so again, we multiply numerator and denominator in this:

3*3=9, 4*3=12:

9/12

So:

(1/2)^2 = 3/12, 2/3 = 8/12, and 0.75 = 9/12

3/12 is smaller than 8/12, and 8/12 is smaller than 9/12. This can be written as:

3/12 < 8/12 < 9/12

And this basically means that:

(1/2)^2 < 2/3 < 0.75

This is the last answer in your answer list.

Hope this helps!

7 0
3 years ago
What is (7-4i)+(-2+5i)
Alla [95]

Answer:

(7-4i)+(-2+5i) = 5 + i

Answer =  5 + i

Step-by-step explanation:

Group the real part and the imaginary part of the complex number

( 7 - 4i ) + (-2 + 5i )

= ( 7 - 2 ) + ( -4 + 5 ) i

Refine = 5 + i

5 0
3 years ago
Read 2 more answers
The equation 3x + 2 = 29 is modeled below.
DanielleElmas [232]

Answer:

Subtract 2 from both sides.

Step-by-step explanation:

Remember to do the opposite of PEMDAS. PEMDAS is the order of operation, and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

> Also, note the equal sign, what you do to one side, you do to the other side of the equation.

First step is to subtract 2 from both sides of the equation:

3x + 2 (-2) = 29 (-2)

3x = 29 - 2

3x = 27

The second step is to divide 3 from both sides of the equation:

(3x)/3 = (27)/3

x = 27/3

x = 9

~

7 0
3 years ago
Read 2 more answers
What is the simplest fprm of x^2+5x-6/x^2+9x+18​
Liono4ka [1.6K]

Answer:

x - 1\x + 3

Step-by-step explanation:

Factoring quadratic expressions with a Leading Coefficient of 1 → In the first equation, you have to find two numbers that when differed to 5, they also multiply to 6, and those numbers are 1 and 6. Now, the tough part for you might be figuring out which term gets which sign. Well, if you look at your MIDST term [5], you would know that the negative symbol goes to 1 [-1] and the positive symbol goes to 6, so your numerator is <em>[</em><em>x</em><em> </em><em>-</em><em> </em><em>1</em><em>]</em><em>[</em><em>x</em><em> </em><em>+</em><em> </em><em>6</em><em>]</em><em>.</em><em> </em>Now, for the second equation, it is applied the same way, but in this case, we need two numbers that when added to 9, they also multiply to 18, and those numbers are 3 and 6, and automatically receive positive symbols, so your denominator is <em>[</em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em>]</em><em>[</em><em>x</em><em> </em><em>+</em><em> </em><em>6</em><em>]</em><em>.</em><em> </em>Now that we have our denominator and numerator, we now set it up: [x - 1][x + 6]\[x + 6][x + 3]. What do you see that is... MAGIC--AL? That is correct! The factors <em>x</em><em> </em><em>-</em><em> </em><em>6</em><em> </em>neutralize each other and are left with <em>x - 1\x + </em><em>3</em><em>.</em>

To be honest, if you had posted quadratic expressions with Leading Coefficients greater than 1, that would be a little bit more tough for you, meaning taking extra steps further, but if you post one in the future, it will be there to assist you because as always...,

I am joyous to assist anyone at any time.

5 0
3 years ago
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