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zubka84 [21]
3 years ago
5

Write -4 _ 7 as a decimal.

Mathematics
1 answer:
Aleksandr [31]3 years ago
5 0
This is super easy all you have to do is divide

-4/7

Which would be -0.57 or rounded 0.6
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Let n=1. Then n^3-n=1^3-1=0. By convention, every non-zero integer n divides 0, so 3\vert n^3-n.

Suppose this relation holds for n=k, i.e. 3\vert k^3-k. We then hope to show it must also hold for n=k+1.

You have

(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)

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Neeeeeed the help please
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The correct answer is -5/7. Hope this helps.
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