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3 years ago

1 Given: AACB = APRQ and

Mathematics

1 answer:

IgorC [24]3 years ago

6 0

Answer:

Nothing

Step-by-step explanation:

<PRQ and <RQP are not the same angle, so we cannot apply the transitive property.

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Someone pls help, its on trig ratios.

Mars2501 [29]

Answer:

$BC=12.8,\\AC=15.1$

Step-by-step explanation:

In right triangles only, the tangent of an angle is equal to its opposite side divided by its adjacent side.

Therefore, we have the following equation:

$\tan 58^{\circ}=\frac{BC}{8}$

Solving, we get:

$BC=8\tan 58^{\circ}\approx \boxed{12.8}$

Also in right triangles only, the cosine of an angle is equal to its adjacent side divided by the hypotenuse of the triangle.

$\cos 58^{\circ}=\frac{8}{AC},\\AC=\frac{8}{\cos 58^{\circ}},\\AC\approx \boxed{15.1}$

We can also use the Pythagorean theorem now that we've found BC. However, if you choose to do so, make sure you don't use a rounded value for BC, as that could cause a notable deviation in your final answer.

Using the Pythagorean theorem to verify our answers:

$8^2+(8\tan 58^{\circ})^2=\left(\frac{8}{\cos 58^{\circ}}\right)^2\:\checkmark$

6 0

3 years ago

Determine whether a triangle can be formed with the given side lengths. 11 ft, 2 ft, 15 ft

dimulka [17.4K]

No it can not be formed because the sum of the two smaller side lengths is not greater than the longest length

6 0

3 years ago

Read 2 more answers

Robbie had p coins. Then he found 59 more coins in a drawer. Choose the expression that shows how many coins Robbie has now.

attashe74 [19]

Answer:

y=p+59

Step-by-step explanation:

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3 years ago

Which expression is equivalent to 10x - (8x +3)

Verdich [7]

Answer:

you forgot to add the options of the answer

5 0

3 years ago

Jorge is building a train set for his cousin. He has a piece of plywood that measures 49.5 inches in length, and he needs 2.25 i

Arada [10]

Answer: 22 pieces

Step-by-step explanation:

You have to divide 49.5 ÷ 2.25

49.5÷2.25= 22

Jorge can cut 22 pieces of plywood for the tracks.

3 0

3 years ago