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Ivan
3 years ago
6

If the length of a rectangle is 5y-7 and the width is 3y,represent the area of the rectangle

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

15y^2 - 21y

Step-by-step explanation:

A = LW

A = (5y - 7)(3y)

A = 15y^2 - 21y

KATRIN_1 [288]3 years ago
8 0

Answer:

A = 15y² - 21y

Step-by-step explanation:

3y(5y - 7)

15y² - 21y

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Step-by-step explanation:

4 bags of bananas for $22.52

=> 2 bags of bananas for $22.52 * 2/4 = $11.26.

Hence it would cost $11.26.

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3 years ago
A new restaurant is attracting customers with searchlights has a radius of 2 feet. What is the searchlights circumference?
Assoli18 [71]

Answer:

12.56 feet

Step-by-step explanation:

The perimeter of a shape is the sum of all its side.

Since circle doesn't have "sides", the perimeter is the length of the whole circle. This has the name "circumference".

The circumference of a circle has the formula:

C=2\pi r

Where

C is the circumference (perimeter of a circle)

r is the radius

Given,

r = 2 feet

We substitute and find the circumference, using 3.14 as \pi,

C=2\pi r\\C=2(3.14) (2)\\C=12.56

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3 years ago
How do you calculate tan^-1 (10/53)
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Use you calculator.

Step-by-step explanation:

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3 years ago
Put the amounts in order from least to greatest... 25 pints, 3 gallons, 46 cups, and 11 quarts
Lunna [17]

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Is the mean weight of female college students still 59.4 kg? To test this, you take a random sample of 20 students, finding a me
adell [148]

Answer:

Correct option: (B)

Step-by-step explanation:

A one-sample <em>t</em>-test can be performed to determine whether the mean weight of female college students is still 59.4 kg.

The hypothesis can be defined as:

<em>H₀</em>: The mean weight of female college students has changed.

<em>Hₐ</em>: The mean weight of female college students has not changed.

The information provided is:

\bar x=61.65\\s=6.39\\n=20\\\alpha =0.10

As the there is no information about the population standard deviation we will use a <em>t</em>-test for the mean.

The test statistic is:

t=\frac{\bar x-\mu}{\s/\sqrt{n}}=\frac{61.65-59.4}{6.39/\sqrt{20}}=1.57

Decision rule:

If the if the <em>p</em>-value of the test is less than the significance level of the test <em>α</em> then the null hypothesis will be rejected and vice versa.

The degrees of freedom of the test is:

df=n-1=20-1=19

The test is two-tailed.

Compute the <em>p</em>-value of the test as follows:

p-value=2\times P(t_{0.10/2, 19}

*Use a <em>t</em>-table for the probability.

The <em>p</em>-value = 0.13 > <em>α</em> = 0.10

The null hypothesis was failed to be rejected.

As the null hypothesis was rejected it can be concluded that there is not sufficient evidence that the mean weight of female students has changed.

6 0
4 years ago
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