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IgorC [24]
3 years ago
6

Someone pls pls pls solve this!!!!!!! And pls explain how u solved it. I need this due rn ASAP!!!

Mathematics
1 answer:
Natalija [7]3 years ago
6 0

35°..

can also be 145° but not in this case since the angle is less than 90°

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Are the parentheses and brackets correct
marshall27 [118]

Answer:

the range is correct

but the domain is [-3,3)

7 0
4 years ago
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Give the proportion a/b = c/d<br> Solve for c
dybincka [34]

Answer:

the answer is c = (ad)/b

Step-by-step explanation:

See the picture

5 0
3 years ago
If 11 - 3x = x, then 20x=
dimaraw [331]

Answer:

20x = 55

Step-by-step explanation:

First you have to add 3x to both sides of 11-3x=x

11-3x=x\\+3x=+3x\\11=4x

Now that you have 11 = 4x you divide 4 on both sides \frac{11}{4} =\frac{4x}{4}

11/4 = x

But you can't divide 11 by 4 unless you are looking for the decimal form of 11/4 which is 2.75

so now we take 11/4 or 2.75 depending on if you need your answer in fraction or as a decimal and replace that with x  however both will equal the number 55

20(\frac{11}{4})=55\\20(2.75)=55

4 0
3 years ago
Find the area of the shaded region. Round the nearest hundredth if necessary. YZ=14.2m
andreyandreev [35.5K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

1

   A_1  =  67.58 \ in^2

2

   A_2 =415.4 \ ft^2

3

   A_3  =  8.48 \ cm^2

4

  A_4 =  480.38 \ m^2

Step-by-step explanation:

Generally the area of a sector is mathematically represented as

         A =  \frac{\theta}{360} * \pi r^2

Now at r_1  = 11 in and  \theta_1 =  64^o

       A_1 =  \frac{64}{360} * 3.142  * 11^2

       A_1  =  67.58 \ in^2

Now at  r_2  = 20 ft in and  \theta_2  =  119 ^o

       A_2 =  \frac{119}{360} * 3.142 *  20^2

       A_2 =415.4 \ ft^2

Now at  r_3  = 6.5 cm   and  \theta_3 =  23 ^o

     A_3  =  \frac{23}{360} * 3.142 *  6.5 ^2

      A_3  =  8.48 \ cm^2

Now at  r_4  = 14.2 m   and  \theta_4 = 360 -87 =  273 ^o

         A_4 =  \frac{273}{360}  * 3.142 * 14.2^2

          A_4 =  480.38 \ m^2

6 0
3 years ago
The first two numbers in a sequence h are h(1) = 2 and h(2) = 6.
Ghella [55]

Answer:

Step-by-step explanation:

Given the first two numbers of a sequence as 2, 6...

If it is an arithmetic difference, the common difference will be d = 6-2 = 4

Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d

a is the first term = 2

d is the common difference = 4

n is the number if terms

Substituting the given values in the formula.

Nth term Tn = 2+(n-1)4

Tn = 2+4n-4

Tn = 4n-4+2

Tn = 4n-2

2) If the sequence us a geometric sequence

Nth term of the sequence Tn = ar^(n-1)

r is the common ratio

r is gotten by the ratio of the terms I.e

r = T2/T1

r = 6/2

r = 3

Since a = 2

Tn = 2(3)^(n-1)

Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)

3 0
3 years ago
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