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3 years ago

11

Please help me! Thank you!

1 answer:

love history [14]3 years ago

7 0

Answer:

Graph A?

Step-by-step explanation:

Just trying to help, but I don't really know. I would say A because its a HUGE jump, but B is a steady incline, but assuming that A has the little incline in the beginning, and then the jump, then back to the incline, probably A would be more profitable.

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If you set aside $9000 at the end of each year for the next 22 years in a Roth IRA, how much will you have at your retirement 22

madam [21]

Answer:

$501,049.37

Step-by-step explanation:

For computing the amount after 22 years we need to applied the future value which is shown in the attachment below:

Given that

PMT = $9,000

NPER = 22 years

Annual rate = 0.078

Quarterly= 0.078 ÷ 4 = 0.0195

Effective annual rate = (1.0195^4) - 1 = 0.0803113041

Now applied the formula which is given below

= -FV(RATE;NPER;PMT;PV)

After applying the above formula, the future value is $501,049.37

7 0

3 years ago

kifflom [539]

20 cats * ( 1 bag of food / 5 cats per month ) = 4 bags of food per month to feed all 20 cats

4 0

3 years ago

Read 2 more answers

If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

Effectus [21]

If A and B are independent, then $P(A\cap B)=P(A)P(B)$ .

a.

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)$

$P(A\cup B)=0.5+0.2-0.5\cdot0.2$

$\boxed{P(A\cup B)=0.6}$

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

$P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)$

$P(A^c\cap B^c)=1-0.6$

$\boxed{P(A^c\cap B^c)=0.4}$

c. DeMorgan's law can be used here too:

$P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)$

$P(A^c\cup B^c)=1-0.5\cdot0.2$

$\boxed{P(A^c\cup B^c)=0.9}$

4 0

2 years ago

Help me with all ten and i will mark u brainlist owo

Gnoma [55]

Answer:

Chile all 10 QuEsTiOns. My brain died.

3 0

2 years ago

Write 235 using powers of 10

vaieri [72.5K]

Answer:

(10^2)*2, 10*3, 10/2

Step-by-step explanation:

Thats my best guess to your very vague question

8 0

2 years ago