All categories

3 years ago

Which equation represents the line that passes through points (2, 0) and (6, -8)?

1 answer:

4 0

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-8}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-8}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}}\implies \cfrac{-8}{4}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-2}(x-\stackrel{x_1}{2})\implies y=-2x+4$

You might be interested in

. The manager of a local small bank wants to estimate the average daily balance of all the checking accounts. Assume a random sa

MaRussiya [10]

Answer:

A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68

Step-by-step explanation:

Consider the provided information.

A random sample of 21 checking accounts at the bank are chosen,

That means n=21

df = n-1

df = 21-1=20

We need to Construct and interpret a 95% confidence interval.

Determine t critical value for 95% confidence interval.

0.95=1-α

α=0.05

The sample size is small and it is a two tailed test.

From the t value table confidence interval is 2.086

An average daily balance is $303 and a standard deviation of $63.

$CI=\bar x\pm t_c \times \frac{s}{\sqrt{n}}$

Substitute the respective values.

$CI=303\pm 2.086 \times \frac{63}{\sqrt{21}}$

$CI=303\pm 28.68$

$CI=274.32\ or\ 331.68$

A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68

3 0

4 years ago

Quadrilateral RPQS is a rectangle. Label the missing measures.

Taya2010 [7]

Answer:

Part 1) $PR=9\ units$

Part 2) $PQ=12\ units$

Part 3) $PS=15\ units$

part 4) $QR=15\ units$

Part 5) $RT=7.5\ units$

Step-by-step explanation:

we know that

In a rectangle opposite sides are parallel and congruent

The measure of each interior angle is 90 degrees

The diagonals are congruent and bisect each other

step 1

Find the length of side PR

we know that

$PR=QS$ ----> by opposite sides

we have

$QS=9\ units$

therefore

$PR=9\ units$

step 2

Find the length of side PQ

we know that

$PQ=RS$ ----> by opposite sides

we have

$RS=12\ units$

therefore

$PQ=12\ units$

step 3

Find the length of diagonal PS

we know that

$PS=2PT$ ---> the diagonals bisect each other

we have

$PT=7.5\ units$ ---> given problem

therefore

$PS=2(7.5)=15\ units$

step 4

Find the length of diagonal QR

we know that

$QR=PS$ ---> the diagonals are congruent

we have

$PS=15\ units$

therefore

$QR=15\ units$

step 5

Find the length of RT

we know that

$QR=2RT$ ---> the diagonals bisect each other

we have

$QR=15\ units$

substitute

$15=2RT\\RT=7.5\ units$

7 0

3 years ago

The value of g(-3) is

valina [46]

Answer:

-3g

Step-by-step explanation:

4 0

3 years ago

solve the problem.a ball is kicked upward with an initial velocity of 68 feet per second. the ball's height, h (in feet), from t

joja [24]

The practical domain of time is t ∈ [0, 4.25s].

The set of values that make feel in a particular context is referred to as the sensible area.
All feasible solutions are addressed by way of theoretical domains and stages.
domain names and stages restrict the solution sets such that they may be realistic in the parameters given
.The ball begins its motion at time t = 0s.
To locate the time while the ball hits the floor,
we solve the equation:
h(t) = -16t² + 68t
h(t) = 0
-16t² + 68t = 0
t(-16t + 68) = 0
t = 0 and -16t + 68 = 0.
16t = 68
t = 68/16
t = 4.25
h(t) is non-negative within the interval [0, 4.25].
Hence, the practical domain is 0 ≤ t ≤ 4.25 s.

To learn more about domain, visit :

brainly.com/question/28135761

#SPJ4

3 0

2 years ago

A line segment with endpoints A(-4, 3, 2) and B(5, -6, -1) is translated first two units back and 3 units right and 1 unit up th

DIA [1.3K]

Answer:

Option B. (3,-10,0) is the right answer.

Step-by-step explanation:

In these questions we should always remember x-axis represents a line in front of us, y-axis represents a line horizontally perpendicular to the line representing x-axis and Z- axis is vertically perpendicular to the x and y- axis.

So shifting front or back means it's a change on x- axis coordinates, shifting right or left means translated on y-axis and moving up and down means translated on z- axis.

Now point for B(5, -6, -1)

x- axis -- 5 - 2 (shifted 2 units back means moved back on x-axis)

y- axis -- (-6) + 3 (shifted 3 units right means right movement on y-axis)

z-axis -- (-1) + 1 ( shifted 1 unit up means increase in z coordinate)

So the new endpoint will be B'(2, -3, 0)

Now as per question image is further translated 7 units left that means

y-axis -- -3 + (-7) (shifted 7 to the left on y axis)

Therefore new end point will be (3, -10, 0).

7 0

4 years ago