Answer:
x=2
Step-by-step explanation:
on the LHS multiply the 6 by the values in the brackets and add by 2x= 9-(x+6) RHS
for the RHS multiply the - by (x+6) which will be 9-x-6
therefore you'll put in your like terms towards the end it'll be 6x-12=0 then take it to the other side and divide by 6 which will give you 2
Answer:
See below ↓↓↓
Step-by-step explanation:
<u>Probability of getting heads</u>
- Outcome (head) = 1
- Total outcomes = 2
- P (head) = <u>1/2</u>
<u></u>
<u>Probability of getting an odd number</u>
- Outcome (odd) = {1, 3, 5} = 3
- Total outcomes = 6
- P (odd) = 3/6 = <u>1/2</u>
<u></u>
The outcomes are equally likely because the probabiity of each outcome is the same.
Answer:
x=−
1.6875
:)))))))))))))))))))))))))
Complete Question
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)
t=8.169
P-value= ?
Answer:
a) 
b) Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
Step-by-step explanation:
From the question we are told that:
Sample size 
Mean 
Standard deviation 
Significance level is taken as 
t test statistics

Therefore

Critical point



Therefore
P-value from T distribution table

Conclusion

We Reject the Null Hypothesis 
Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.