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VARVARA [1.3K]
3 years ago
8

| When solving a system of equations, Jared found y = x +

Mathematics
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

Both Jared and Nicole are correct. You can solve for either variable and use the equivalent expression to create a one-variable equation. Then you can solve. Jared would have created a one-variable equation that can be used to solve for x, whereas Nicole would have created a one-variable equation that can be used to solve for y.

borishaifa [10]3 years ago
4 0

Answer:

They are both correct in their procedure. Nicole solved for one variable in the equation, while Jared solved for the other variable.

Step-by-step explanation:

Notice that if you have the equation  y = x + 10 in a system of equations, the most immediate thing to do is to try to use the fact that "y" is the same as "x + 10" to substitute in the other equation of the system.

But, this same equation can also be used to solve for the other variable "y", by simply subtracting 10 from both sides, which gives:

y - 10 = x

So now, one can use "y-10" to substitute for x in the other equation.

Both procedures are correct, and simply will lead to finding a different variable first when solving the equation.

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Step-by-step explanation:

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Read 2 more answers
Help? Please. Thanks???
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The height is represented by d.

d = 10 feet

10 = -  16 {t}^{2}  - 7t + 61 \\ 0 =  - 16 {t}^{2}  - 7t + 51

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3 0
3 years ago
WILL MARK BRAINLIEST
Levart [38]

Answer:

Part 1:

The solution set of the system of equations is x = 1, y = 1

Part 2:

The solution set is x = 1, y = 1

Part 3:

The similarity of the system of equations in Parts 1 and 2 is that they have the same solution set

The difference of the system of equations in Parts 1 and 2 is that they are arranged differently

Step-by-step explanation:

Part 1:

The system of equation is given as follows;

2·x + y = 3...(1)

x = 2·y - 1...(2)

The above system of equations can be written in terms of the variable, y, as follows;

For equation (1), we have;

y = 3 - 2·x

For equation (2), we have;

y = (x + 1)/2

From the attached graph created with Microsoft Excel, we have;

The solution set (the point of intersection) of the system of equations is x = 1, y = 1

To accurately find the common solution, we have;

(x + 1)/2 = 3 - 2·x

x + 1 = 2·(3 - 2·x) = 6 - 4·x

x + 1 = 6 - 4·x

x + 4·x = 6 - 1

5·x = 5

x = 5/5 = 1

x = 1

Therefore, y = 3 - 2·x = 3 - 2× 1 = 1, at the common solution

Part 2:

y = -2x + 3

x - 2y = -1

∴ x = 2y -1

y = -2(2y -1) + 3

y = -4y + 2 + 3

5y = 5

y = 1

x = 2y - 1 = 2 - 1 = 1

x = 1

The solution set is x = 1, y = 1

Part 3

The system of equations are similar in terms of their solution

The system of equations are different in terms of their arrangement

6 0
2 years ago
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