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3 years ago

I need help ASP. Help

Mathematics

1 answer:

rosijanka [135]3 years ago

5 0

What you do is start off with looking at one box at a time then you will then multiply length times width once you do every box add up each product and that will be you final anwser

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Gordon types 2,772 words in 42 minutes. Find the unit rate.

zubka84 [21]

Answer:

66 words in 1 minute

I hope this helps!

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2 years ago

Use the quadratic formula to solve the equation. -2x^2-x+7=0.

Furkat [3]

<span>-2x^2-x+7=0
Variable with the highest degree's (exponent) constant, -2 is a, next variable's constant, -1 is b, the constant or number without a variable, 7 is c

using substitution put the numbers into the formula
</span>(-b±√(b^(2)-4ac))/(a^(2))

(-(-1)±√((-1)^(2)-4(-2)(7))/((-2)^(2)) simplify

(1±√(1+56))/4

1±√(57)/4 is your answer

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2 years ago

Help me please!!!!!!!

NARA [144]

Answer:

sorry can't help hope someone gets it

6 0

2 years ago

Which modified box plot represents the data set? 10, 12, 2, 4, 24, 2, 7, 7, 9

Ratling [72]

The fourth option is the answer. When graphed, Min is 2, Q1 is 3, Median is 7, Q3 is 11, and Max is 24. The fourth option is the one that follow all of those!

7 0

3 years ago

Read 2 more answers

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago