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PilotLPTM [1.2K]
3 years ago
11

What is the output of the code snippet given below?string s = "abcde";int i = 1;while (i < 5){ cout << s.substr (i, 1);

i++;}a. no outputb. abcdc. abcde d. bcde
Computers and Technology
1 answer:
Ronch [10]3 years ago
4 0

Answer:

The answer is "Option d".

Explanation:

In the given C++ program code, two-variable is defined, that is "s and i", in which variable s is a string type that holds a value, that is "abcde", and variable i is an integer type, that holds a value '1'.

  • In the next line, a while loop is declared, that uses integer variable which value is less than 5, inside a loop a substring function is used, that specifies the number of character and return its value.  
  • In array and string indexing starts from 0, and that variable i starts from 1, that is used in substring function, that's why it will print only "bcde".
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A customer reports that recently several files cannot be accessed. The service technician decides to check the hard disk status
Lyrx [107]

Answer:

Back up the user data to removable disk

Explanation:

Before you work on a computer, especially anything that has to do with files not accessible, this might need to format the system because it might either be a virus or other forms of malware. Since backup was done to a different logical partition on the disk, the first thing to do before performing any diagnostic procedures on the disk is to back up the user data to a removable disk in order not to lose the information in the system.

8 0
3 years ago
Type (dog, cat, budgie, lizard, horse, etc.) Create a class that keeps track of the attributes above for pet records at the anim
Alenkinab [10]

Answer:

If you did the exercise with two Dog objects, it was a bit boring, right? After all, we have nothing to separate the dogs from each other and no way of knowing, without looking at the source code, which dog produced which bark.

In the previous article, I mentioned that when you create objects, you call a special method called a constructor. The constructor looks like the class name written as a method. For example, for a Dog class, the constructor would be called Dog().

The special thing about constructors is that they are the path to any new object, so they are a great place to call code that initializes an object with default values. Further, the return value from a constructor method is always an object of the class itself, which is why we can assign the return value of the constructor to a variable of the type of class we create.

However, so far, we have not actually created a constructor at all, so how come we can still call that method?

In many languages, C# included, the language gives you a free and empty constructor without you having to do anything. It is implied that you want a constructor; otherwise there would be no way of using the class for anything, so the languages just assume that you have written one.

This invisible and free constructor is called the default constructor, and, in our example, it will look like this:

public Dog(){ }

Notice that this syntax is very similar to the Speak() method we created earlier, except that we do not explicitly return a value nor do we even declare the return type of the method. As I mentioned earlier, a constructor always returns an instance of the class to which it belongs.

In this case, that is the class Dog, and that is why when we write Dog myDog = new Dog(), we can assign the new object to a variable named myDog which is of type Dog.

So let’s add the default constructor to our Dog class. You can either copy the line above or, in Visual Studio, you can use a shortcut: type ctor and hit Tab twice. It should generate the default constructor for you.

The default constructor doesn’t actually give us anything new because it is now explicitly doing what was done implicitly before. However, it is a method, so we can now add content inside the brackets that will execute whenever we call this constructor. And because the constructor runs as the very first thing in an object’s construction, it is a perfect place to add initialization code.

For example, we could set the Name property of our objects to something by adding code such as this:

public Dog()

{

   this.Name = "Snoopy";

}

This example will set the Name property of any new objects to “Snoopy”.

Of course, that’s not very useful because not all dogs are called “Snoopy”, so instead, let us change the method signature of the constructor so that it accepts a parameter.

The parentheses of methods aren’t just there to look pretty; they serve to contain parameters that we can use to pass values to a method. This function applies to all methods, not just constructors, but let’s do it for a constructor first.

Change the default constructor signature to this:

public Dog(string dogName)

This addition allows us to send a string parameter into the constructor, and that when we do, we can refer to that parameter by the name dogName.

Then, add the following line to the method block:

this.Name = dogName;

This line sets this object’s property Name to the parameter we sent into the constructor.

Note that when you change the constructor’s signature, you get a case of the red squigglies in your Program.cs file.When we add our own explicit constructors, C# and .NET will not implicitly create a default constructor for us. In our Program.cs file, we are still creating the Dog objects using the default parameter-less constructor, which now no longer exists.

To fix this problem, we need to add a parameter to our constructor call in Program.cs. We can, for example, update our object construction line as such:

Dog myDog = new Dog(“Snoopy”);

Doing so will remove the red squigglies and allow you to run the code again. If you leave or set your breakpoint after the last code line, you can look at the Locals panel and verify that your object’s Name property has indeed been? Got it?

5 0
2 years ago
Sending an identical message in an e-mail blast to all customers is an example of
disa [49]

Answer:

Broadcast message

Explanation:

A broadcast message is an identical message sent to a lot of recipients. When it is an email, it can be sent in Carbon Copy (Cc) or a Blind Carbon Copy (Bcc) form.

With the<em> Carbon Copy</em>, every recipients will be notified about the other recipients. In most cases all the email usernames of the recipients will be sent to all the recipients individually.

With the <em>Blind Carbon Copy</em>, every individual sees the message as he/she received it alone. The individual is not notified about the other recipients.

8 0
3 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
In Python, if var1 = “Happy” and var2= “Birthday” and var3 = (var1+var2) *2, then var3 stores the string
-Dominant- [34]

Answer:

A

Explanation:

var3 is happy + birthday, ×2

l.e happy birthday happy birthday

3 0
3 years ago
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