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2 years ago

5

Given the line 2y=−3x+5 , determine the relationship to the line below. Is it perpendicular, parallel, intersecting (but not per

pendicular), or coinciding? 6y=−9x+15

1 answer:

aliya0001 [1]2 years ago

6 0

Answer:

coinciding

Step-by-step explanation:

If you divide the second equation by 3, you get the first equation. They describe the same line, so the lines are <em>coinciding</em>.

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iren2701 [21]

<h3>Answer: triangular prism </h3>

Step-by-step explanation:

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2 years ago

What’s 9+10? (I will give Brainliest!)

Allushta [10]

Answer:

19

Step-by-step explanation:

9+10 is 19

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1 year ago

Read 2 more answers

Find the slope of ( 3,7 ) ( 4,10 )

Dominik [7]

The slope is 3.

10 - 7 = 3
4 - 3 = 1

Final step is to do 3 divided by 1 and you get 3.

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2 years ago

The sum of two numbers is -17 and their difference is 41 what are the two numbers?

liberstina [14]

Answer: the two numbers are 7 and -27

Step-by-step explanation:

Let the two numbers be a and b

From the question,

a + b = -27.......eqn 1

a - b = 41............eqn 2

Sum the two equations

2a = 14

Divide both sides by 2

a = 14/2; a = 7

Substitute a = 7 into equation 2

a - b = 41

7 - b = 41

Make b the subject of the equation

-b = 41 -7

-b = 34

b = -34

Check:

a + b = -27, slot the values of a and b

7 + (-34) = -27

7- 34 = -27

I hope this is clear, please mark as brainliest answer

7 0

2 years ago

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

2 years ago